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butalik [34]
3 years ago
7

How is momentum of an object related to stopping distance​

Physics
1 answer:
Rama09 [41]3 years ago
6 0

Answer:

To stop a car must lose its momentum and its kinetic energy. ... If the forces on two cars are equal then the greater the kinetic energy the greater the distance before stopping. But there will be a relationship to the momentum because momentum and mass are both related to the kinetic energy.

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Two 60 cm parallel disks are separated by 40 cm and are aligned directly on top of each other. Both disks are black surfaces wit
Crazy boy [7]

Answer:

775.48 W

Explanation:

given,

diameter of disk = 0.6 cm

length of the disk = 0.4 m

T₁ = 450 K         T₂ = 450 K      T₃ = 300 K

\dfrac{d}{r_1}=\dfrac{0.4}{0.3} = 1.33

now,

the value of view factor (F₁₂)corresponding to 1.33

F₁₂ = 0.265

F₁₃ = 1 - 0.265 = 0.735

now,

net rate of radiation heat transfer from the disk to the environment:

=\dot{Q_{1-3}+Q_{2-3}} = 2 \dot{Q_{1-3}}

       = 2 F₁₃ A₁ σ (T₁⁴ - T₃⁴)

       = 2 x 0.735 x π x (0.3)² x (5.67 x 10⁻⁸ W/m²) (450⁴ - 300⁴)

       = 775.48 W

Net radiation heat transfer from the disks to the environment = 775.48 W

3 0
4 years ago
An infant galaxy that is studied through the use of radio waves?
Tom [10]
An infant galaxy that is studied through the use of radio waves is called QUASAR.
Quasar are astronomical object, which have very high luminosity and they are found in the centers of some galaxies. Scientists believed that quasar are centers of distant galaxies. Radio waves is used to study quasar because they emit a huge amount of radio waves. 
4 0
3 years ago
The ear drum vibrates when struck by sound waves and directly sends a message to the brain that is then recognized as sound
erma4kov [3.2K]

Answer:

true

Explanation:

4 0
3 years ago
all bearings are made by lebng spherical drops of molten metal fall inside a tall tower – called a shot tower – and solidify as
Wewaii [24]

Answer:

Part b)

h = 78.5 m

Part c)

v = 39.24 m/s

Explanation:

Part b)

If ball need t = 0 to t = 4 s then height of the tower is the total displacement of the ball in t = 4 s interval

here if ball start from rest

then its displacement is given as

\Delta y = \frac{1}{2}gt^2

\Delta y = \frac{1}{2}(9.81)(4^2)

\Delta y = 78.5 m

Part c)

Speed of the bearing at the end of the motion of the ball

v_f = v_i + at

v_f = 0 + (9.81)(4)

v_f = 39.24 m/s

7 0
3 years ago
What does this mean??
Fudgin [204]
I need help on this too lol
7 0
3 years ago
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