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2 years ago

The diagram below shows the velocity vectors for two cars that are moving relative to each other.

Physics

1 answer:

scoundrel [369]2 years ago

7 0

Answer:

The answer is " $5 \ \frac{m}{s} \ west$ "

Explanation:

$\to \vec{V_1} = (25 \frac{m}{s}) (\hat{-i})\\\\\to \vec{V_2} = (20 \frac{m}{s}) (\hat{-i})\\\\$

velocity of car | respect to car :

$\to \vec{V_{12}} = \vec{V_1} - \vec{V_2}\\\\$

$=\vec{-25} \hat{i}+ \vec{20} \hat{i}\\\\= 5 \ \frac{m}{s} \ west$

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In another solar system is planet Driff, which

Fed [463]

Answer:

It is (1/5)th as much.

Explanation:

If we apply the equation

F = G*m*M / r²

where

m = mass of a man

M₀ = mass of the planet Driff

M = mass of the Earth

r₀ = radius of the planet Driff

r = radius of the Earth

G = The gravitational constant

F = The gravitational force on the Earth

F₀ = The gravitational force on the planet Driff

g = the gravitational acceleration on the surface of the earth

g₀ = the gravitational acceleration on the surface of the planet Driff

we have

F₀ = G*m*M₀ / r₀² = G*m*(5*M) / (5*r)²

⇒ F₀ = G*m*M / (5*r²) = (1/5)*F

F₀ = (1/5)*F

then

W₀ = (1/5)*W ⇒ m*g₀ = (1/5)*m*g ⇒ g₀ = (1/5)*g

It is (1/5)th as much.

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2 years ago

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Answer:

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$\frac{dy}{dt} = \frac{80\pi}{3}$ km/min

Given:

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$\frac{dtan\theta'}{dt} = \frac{dy}{3dt}$

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2 years ago

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