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sleet_krkn [62]

3 years ago

13

When an atom forms negaitive ion?

1 answer:

AlladinOne [14]3 years ago

8 0

Answer:

The outer shells of non metal atoms gain electrons when they form ions this result in the formation of negative ions

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A mixture of oxygen hydrogen and nitrogen gas is exerts a total pressure of 282K PA if the partial pressures of oxygen and hydro

sergiy2304 [10]

Glgggggggggggggggggggggggg

7 0

3 years ago

Read 2 more answers

Terms that have to be used: Products, Reactants, Balanced, Unbalanced, Atoms

emmainna [20.7K]

Answer:

A Chemical equation is balanced if the reactants side of the chemical reaction has the same number total of atoms of elements as the products side of the chemical equation. While a Chemical equation is unbalanced if the reactants side of the chemical reaction has a different number total of atoms of elements as the products side of the chemical equation

Explanation:

Self explanatory

3 0

3 years ago

Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1

givi [52]

According to Hasselbach-Henderson equation:

$pH=pK_{a}+log\frac{[A^{-}]}{[HA]}$

Here, $[A^{-}]$ is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is $CH_{3}COOK$ and acid is $CH_{3}COOH$ thus, Hasselbach-Henderson equation will be as follows:

$pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}$ ...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{2}{1}=5.06$

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{3}=4.28$

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{5}{1}=5.45$

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{1}=4.76$

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{10}=3.76$

Therefore, pH of solution is 3.76.

4 0

3 years ago

What is related to the energy of motion of the particles of matter?

Amanda [17]

The Kinitec Molecular Theory of Matter
Yes Kninetic energy

5 0

4 years ago

What is the molarity of a solution containing 5 moles of HCl in 2.5 L of solution? Be sure to include the formula for calculatin

beks73 [17]

Answer:

$\boxed{\text{2 mol/L}}$

Step-by-step explanation:

$c = \dfrac{ \text{moles} }{ \text{litres}}\\\\c = \dfrac{n }{V }$

Data:

n = 5 mol

V = 2.5 L

Calculation:

$c = \dfrac{ \text{5 mol} }{\text{2.5 L}} = \text{2 mol/L}$

The molar concentration of the solution is $\boxed{\textbf{2 mol/L}}$ .

6 0

3 years ago