16 ÷ (4)(2) - 3(2) <span>÷ 2+1
16 </span>÷ 8 - 6 <span>÷ 3
2 - 2
0
Answer: 0</span>
It’s the 3rd one hopefully this helps
For the first line we have a slope of (y2-y1)/(x2-x1)
(2--2)/(1--1)=4/2=2 so we have:
y=2x+b, now solve for b with either of the points, I'll use: (1,2)
2=2(1)+b
b=0 so the first line is:
y=2x
Now the second line:
(1-10)/(4--2)=-9/6=-3/2 so far then we have:
y=-3x/2+b, using point (4,1) we solve for b...
1=-3(4)/2+b
1=-6+b
b=7 so
y=-3x/2+7 or more neatly...
y=(-3x+14)/2
...
The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...
2x=(-3x+14)/2
4x=-3x+14
7x=14
x=2, and using y=2x we see that:
y=2(2)=4, so the solution occurs at the point:
(2,4)
Answer:
It would be 55.88 but if you round it it would be 55.9 then round it again it would be 56%.
The translation of the question given is
A line that passes through the points A (2,1) and B (6,3) and another line passes through A and through the point (0, y). What is y worth, if both lines are perpendicular?
Answer:
y = 5
Step-by-step explanation:
Line 1 that passes through A (2,1) and B (6,3)
Slope (m1) = 3-1/6-2 = 2/4 = 1/2
y - 1 = 
( x -2)
2y - 2 = x- 2
y = 
Line 2 passes through A (2,1) and (0,y)
slope (m2) =
Line 1 and Line 2 are perpendicular
m1*m2 = -1
* = -1
y-1 = 4
y = 5
slope = -2
Equation of Line 2
Y-1 = -2(x-2)
y -1 = -2x +4
2x +y = 5
