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PilotLPTM [1.2K]
2 years ago
6

Which elements can have expanded octets?

Chemistry
1 answer:
PSYCHO15rus [73]2 years ago
7 0

Answer:

Sulfur, phosphorus, silicon, and chlorine are common examples of elements that form an expanded octet.

Explanation:

Phosphorus pentachloride (PCl5) and sulfur hexafluoride (SF6) are examples of molecules that deviate from the octet rule by having more than 8 electrons around the central atom

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Which area should have the lowest temperatures?<br><br> A. 1<br><br> B.2 <br><br> C.3 <br><br> D.4
pochemuha

Answer:

A. 1

Explanation:

The higher you get in the atmosphere the cooler the temperature will be. The reason it's actually colder is because, as you go up in the atmosphere, the Earth's atmosphere feels less pressure the higher up you go. So as the gas in the atmosphere rises it feels less pressure, which makes it expand.

Hope this Help :)

Please mark brainliest :D

7 0
3 years ago
A. 20 moles of NH3 are needed to produce how many moles of H2O?
tiny-mole [99]

a. 30 moles of H₂O

b. 2.33 moles of N₂

<h3>Further explanation</h3>

Given

a. 20 moles of NH₃

b. 3.5 moles of O₂

Required

a. moles of H₂O

b. moles of N₂

Solution

Reaction

4NH₃+3O₂⇒2N₂+6H₂O

a. From the equation, mol ratio NH₃ : H₂O = 4 : 6, so mol H₂O :

=6/4 x mol NH₃

= 6/4 x 20 moles

= 30 moles

b. From the equation, mol ratio N₂ : O₂ = 2 : 3, so mol N₂ :

=2/3 x mol O₂

= 2/3 x 3.5 moles

= 2.33 moles

7 0
3 years ago
1. How much magnesium oxide is produced if 12.1 g of magnesium reacts with 16 g of oxygen
melamori03 [73]

Answer:

20.2g (3 s.f.)

Explanation:

Please see attached picture for full solution.

8 0
3 years ago
using the Bohr model for hydrogen: energy = hc/wavelength = 2.18 x 10^-18 Joules (1/nf2 - 1/ni2) N=15 to n=5
soldier1979 [14.2K]

Answer:

Energy lost is 7.63×10⁻²⁰J

Explanation:

Hello,

I think what the question is requesting is to calculate the energy difference when an excited electron drops from N = 15 to N = 5

E = hc/λ(1/n₂² - 1/n₁²)

n₁ = 15

n₂ = 5

hc/λ = 2.18×10⁻¹⁸J (according to the data)

E = 2.18×10⁻¹⁸ (1/n₂² - 1/n₁²)

E = 2.18×10⁻¹⁸ (1/15² - 1/5²)

E = 2.18×10⁻¹⁸ ×(-0.035)

E = -7.63×10⁻²⁰J

The energy lost is 7.63×10⁻²⁰J

Note : energy is lost / given off when the excited electron jumps from a higher energy level to a lower energy level

5 0
3 years ago
What is matter in chemistry
mixas84 [53]
Matter in chemistry is the weight/mass of something
8 0
4 years ago
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