U could first highlight text, right click then copy, and then Ctrl + v. You could find Ctrl (or control) under the shift button to your left
I hope this helped:D
// making the class
class Counter {
int counter;
int limit;
// Constructor
Counter(int a, int b){
counter = a;
limit = b;
}
// static function to increment
static increment(){
if(counter<limit)
nCounter+=1;
}
// Decrement function
void decrement(){
if(counter>0)
nCounter-=1;
}
int getValue(){
return counter;
}
static int nCounter;
int getNCounters(){
return nCounter;
}
};
// Initializa the static
int Counter::nCounter = 0;
Answer:
The formula is =D3*E3
Explanation:
To multiply the items in 2 cells, the formula like every other in excel begins with = .
to multiply 50 in cell D3 by 8.90 in cell E3 the formula to be used is
=D3*E3
This will multiply the numbers in both cell and show as 445.
Answer:
Teredo tunnelling
Explanation:
The tunnelling method that will fit best in the situation is teredo tunnelling. The reason are embedded in its characteristics, they include;
Teredo tunneling has the following characteristics: Its tunnel endpoints are configured on hosts. The hosts are dual stack hosts and perform tunneling of ipv6 to send on the ipv4 network works through NAT the only solution that allows ipv4-only hosts to communicate with ipv6-only hosts is NAT-PT.
The answer is: [B]: " 2 " .
_____________________________________________
Explanation:
____________________________________
Given the chemical equation:
____________________________________
<u> ? </u> H₂ + O₂ → 2 H₂<span>O ;
____________________________________________
</span> → <span> We are asked, "What coefficient, if any — should be put in front of the: " H</span>₂ " ;
__________________________________________________
(which is on the "left-hand side" side of the chemical equation given— the "reactants") ;
→ to get a balanced chemical equation?
__________________________________________________
→ Let us examine the "right-hand side" of this chemical equation—the product(s). In this case, the "product" given is: " 2 H₂O " .
So, on the "right hand side", we have:
__________________________________________________
1) 4 "H's" → {Two "H₂" 's = 2 * 2 = "4 H's"} ; <u><em>and</em></u>:
2) 2 "O's" → { Two "O's").
__________________________________________________
So, the left-hand side should have:
__________________________________________________
1) 4 "H's" ; <u><em>and</em></u>:
2) 2 "O's" ;
__________________________________________________
Let us examine the left-hand side (the "reactants").
__________________________________________________
" <u> ? </u><u /> H₂ + O₂ " ;
__________________________________________________
On the left-hand side, we already have:
__________________________________________________
1) " 2 O's " ; → one "O₂" = "2 O's" ; and:
2) "2 H's " ; → one "H<span>₂" .</span>
Now, we would need:
__________________________________________________
A "<u>total of "4 H's</u>". Is there any number we could put as a coefficient on the other reactant, which happens to be: "H₂" ; to make a <u><em>total of</em></u> "4 H's" ?
{Note: There are only these TWO (2) reactants in this chemical equation.}.
→ The "H₂" ; as it stands alone, is insufficient—since that would be only "2 H's".
__________________________________________________
→ Thus, we can rule out: "Answer choices: [A] and [D]."
___________________________________________________
<u>Note</u>:
→ Choice [A]: "1" ; The coefficient, "1"; is generally not (never?) used; and basically would function as the same as:
→ Choice: [D]: "<span>no coefficient is needed".
</span>→ <span>Choices [A] & [D]: would leave us with only "2 H's" on the "reactants side" (i.e. "left-hand side of the equation"; and we need FOUR ("4 H's").
__________________________________________________
Since we are given: "H</span>₂" ; what coefficient could we put in front of this to get: "4 H's" ? (4÷2 =2). So we could put a "2" in front of the "H₂" ; to get:
"4 H's". The coefficient, "2" , corresponds directly with:
__________________________________________________
→ Answer choice: [B]: "2" .
_________________________________________________
{ <u>NOTE</u>: The remaining answer choice, [C], which is, "3" ; is INCORRECT; since 3 "H₂'s" would be "6 H's" ; (since 3 * "2 H's" equal "6 H's") ; which is too many "H's" → We need <u>exactly</u> "4 H's".}.
_________________________________________________
So, the correctly balanced equation is:
2 H₂ + O₂ → 2 H₂O ;
_________________________________________________
→ The coefficient that goes before the "H₂" ; to make this chemical equation balanced, is: "2" .
_________________________________________________
The correct answer is: [B]: "2" .
→ The coefficient that goes before the "H₂" is: "2" .
_________________________________________________
Hope this answer—and {lengthy} explanation—is of help!
_________________________________________________
