Answer:
as answered in the attached file.
Explanation:
The detailed steps, derivation and appropriate differentiation is as shown in the attachment
Which of these include some basic characteristics of taxi services? (Select all that apply.)Transactions are often negotiated at
1 answer:
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Answer:
Stat PVC = Stat(82+98.5)
Stat PVT = Stat(59+71.5)
Explanation
PVI = 71 + 35
Let G1 = Grade 1; G2 = Grade 2
G1 = +2.1% ; G2 = -3.4%
Highest point of curve at station = 74 + 10
General equation of a curve:
At highest point of the curve
Station PVT
Answer:
The answer is "+9.05 kw"
Explanation:
In the given question some information is missing which can be given in the following attachment.
The solution to this question can be defined as follows:
let assume that flow is from 1 to 2 then
Q= 1kw
m=0.1 kg/s
From the steady flow energy equation is:
If the sign of the work performed is positive, it means the work is done on the surrounding so, that the expected direction of the flow is right.
