I am not sure I am stuck on this and I have been for 45 min someone please help me and this girl or boy!!
Answer:
The temperature gauge showing that the vehicle has been running warmer or has recently began to have issues from overheating is an idication that your vehicle may be developing a cooling system problem.
Explanation:
Answer:
3A
Explanation:
Using Ohms law U=I×R solve for I by I=U/R
Answer:
import java.util.Scanner;
public class InputExample {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int birthMonth;
int birthYear;
birthMonth = scnr.nextInt();
birthYear = scnr.nextInt();
System.out.println(birthMonth+"/"+birthYear);
}
}
Answer:
Net discharge per hour will be 3.5325 ![m^3/hr](https://tex.z-dn.net/?f=m%5E3%2Fhr)
Explanation:
We have given internal diameter d = 25 mm
Time = 1 hour = 3600 sec
So radius ![r=\frac{d}{2}=\frac{25}{2}=12.5mm=12.5\times 10^{-3}m](https://tex.z-dn.net/?f=r%3D%5Cfrac%7Bd%7D%7B2%7D%3D%5Cfrac%7B25%7D%7B2%7D%3D12.5mm%3D12.5%5Ctimes%2010%5E%7B-3%7Dm)
We know that area is given by
![A=\pi r^2=3.14\times (12.5\times 10^{-3})^2=490.625\times 10^{-6}m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%3D3.14%5Ctimes%20%2812.5%5Ctimes%2010%5E%7B-3%7D%29%5E2%3D490.625%5Ctimes%2010%5E%7B-6%7Dm%5E2)
We know that discharge is given by
, here A is area and V is velocity
So ![Q=AV=490.625\times 10^{-6}\times 2=981.25\times 10^{-6}m^3/sec](https://tex.z-dn.net/?f=Q%3DAV%3D490.625%5Ctimes%2010%5E%7B-6%7D%5Ctimes%202%3D981.25%5Ctimes%2010%5E%7B-6%7Dm%5E3%2Fsec)
So net discharge in 1 hour = ![981.25\times 10^{-6}m^3/sec\times 3600=3.5325m^3/hour](https://tex.z-dn.net/?f=981.25%5Ctimes%2010%5E%7B-6%7Dm%5E3%2Fsec%5Ctimes%203600%3D3.5325m%5E3%2Fhour)