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Darina [25.2K]
3 years ago
10

Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the pr

oduct?A. 2C(s)+H2(g)→C2H2(g); ΔG∘f=209.2 kJ/molB. N2(g)+3H2(g)→2NH3(g); ΔG∘f=−33.30 kJ/molC. 2C(s)+2H2(g)→C2H4(g); ΔG∘f=68.20 kJ/molD. 2SO(g)+O2(g)→2SO2(g); ΔG∘f=−600.4 kJ/mol
Chemistry
1 answer:
Luda [366]3 years ago
7 0

Answer:

Option B and D

Explanation:

The Gibb's free energy also referred to as the gibb's function represented with letter G. it is the amount of useful work obtained from a system at constant temperature and pressure. The standard gibb's free energy on the other hand is a state function represented as Delta-G, as it depends on the initial and final states of the system.

A feasible way to synthesize the product entails the spontaneity of the reaction.

The spontaneity of a reaction is explained by the standard gibb's free energy.

If Delta-G = -ve ( the reaction is spontaneous)

if Delta -G = +ve ( the reaction is non-spontaneous)

if Delta-G = 0 ( the reaction is at equilibrium)

Hence the option (B and D) with negative Gibb's free energy are the reaction that are spontaneous.

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How many moles of N2 in 57.1 g of N2?
SpyIntel [72]

We are given –

  • Mass of \bf N_2 is 57.1 g and we are asked to find number of moles present in 57.1 g of \bf N_2

\qquad\pink{\bf\longrightarrow  { Molar \:mass \:of \: N_2:-}  }

\qquad\bf  \twoheadrightarrow 14\times 2

\qquad\bf \twoheadrightarrow   28

\qquad____________________

Now,Let's calculate the number of moles present in 57.1 g of \bf N_2

\qquad\purple{\bf\longrightarrow  { No \:of \:moles = \dfrac{Given \:mass}{Molar\: mass}}}

\qquad\bf   \twoheadrightarrow \dfrac{57.1}{28}

\qquad\bf  \twoheadrightarrow 2.04\: moles

__________________________________

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2 years ago
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