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Darina [25.2K]
3 years ago
10

Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the pr

oduct?A. 2C(s)+H2(g)→C2H2(g); ΔG∘f=209.2 kJ/molB. N2(g)+3H2(g)→2NH3(g); ΔG∘f=−33.30 kJ/molC. 2C(s)+2H2(g)→C2H4(g); ΔG∘f=68.20 kJ/molD. 2SO(g)+O2(g)→2SO2(g); ΔG∘f=−600.4 kJ/mol
Chemistry
1 answer:
Luda [366]3 years ago
7 0

Answer:

Option B and D

Explanation:

The Gibb's free energy also referred to as the gibb's function represented with letter G. it is the amount of useful work obtained from a system at constant temperature and pressure. The standard gibb's free energy on the other hand is a state function represented as Delta-G, as it depends on the initial and final states of the system.

A feasible way to synthesize the product entails the spontaneity of the reaction.

The spontaneity of a reaction is explained by the standard gibb's free energy.

If Delta-G = -ve ( the reaction is spontaneous)

if Delta -G = +ve ( the reaction is non-spontaneous)

if Delta-G = 0 ( the reaction is at equilibrium)

Hence the option (B and D) with negative Gibb's free energy are the reaction that are spontaneous.

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Under constant pressure a sample of hydrogen gas initially at 88°C and 9.6 L is cooled until its final volume is 3.4 L. What is
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The final temperature = -145.24K or 127°C.

According to the data given,

T1= 88°C = 361.15K

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The final temperature = -145.24K or 127°C

<h3>What does Charles law state?</h3>

According to Charles' law, when the pressure is held constant, the volume of a given amount of gas is precisely proportional to its temperature on the kelvin scale.

<h3>What connection exists between volume and temperature?</h3>
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<h3>What are the applications of Charles law?</h3>
  • A hot air balloon drifting through the air is an illustration of Charles Law in action.
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To learn more about Charles law visit:

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A 250 cm^3 solution containing 1,46 g of sodium chloride is added to an excess of silver nitrate solution. The reaction is given
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Answer:

The mass of the precipitate  that AgCl is 3.5803 g.

Explanation:

a) To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

We are given:

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Volume of solution = 250 cm^3 =250 mL

1 cm^3= 1 ml

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{1.46g\times 1000}{58.5g/mol\times 250}\\\\\text{Molarity of solution}=0.09982 M

0.09982 M is the concentration of the sodium chloride solution.

b) NaCl (aq)+AgNO_3 (aq)\rightarrow AgCI(s)+NaNO_3(aq)

Moles of NaCl = \frac{1.46 g}{58.5 g/mol}=0.02495 mol

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Then 0.02495 moles of NaCl will give:

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