3 years ago

I need help!!! Idk what the answer is

1 answer:

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Translations, reflections, and rotations preserve congruency. Dilations do not?

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Mariulka [41]

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den301095 [7]

Answer:

$P (y < 6) = \frac{P(y- \mu)}{\sigma} \mu}{\sigma} \\\\=P(z$

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618

Step-by-step explanation:

Normal with mean 6.88 minutes and

a standard deviation of 0.57 minutes.

Choose a student at random from this group and call his time for the mile Y. Find P(Y<6)

$\mu = 6.88$

$\sigma = 0.57$

y ≈ normal (μ, σ)

The z score is the value decreased by the mean divided by the standard deviation

$P (y < 6) = \frac{P(y- \mu)}{\sigma} \mu}{\sigma} \\\\=P(z$

Therefore the probability that a randomly selected student has time for mile run is less than 6 minute is 0.0618

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