Question

A tetrahedron has an equilateral triangle base with 25.0-cm-long edges and three equilateral triangle sides. The base is parallel to the ground, and a vertical uniform electric field of strength 260N/C passes upward through the tetrahedron.What is the electric flux through the base?What is the electric flux through each of the three sides?

Answer 1

Answer:

electric flux through the three side = 2.35 N m²/C

Explanation:

given,

equilateral triangle of base = 25 cm

electric field strength = 260 N/C

Area of triangle = $\dfrac{\sqrt{3}}{4}a^2$

                          =  $\dfrac{\sqrt{3}}{4} 0.25^2$

                          = 0.0271 m³

electric flux = E. A

                   = 260 × 0.0271

                   = 7.046 N m²/C

since, tetrahedron does not enclose any charge so, net flux through tetrahedron is zero.

electric flux through the three side = (electric flux through base)/3

                               = $\dfrac{7.046}{3}$

electric flux through the three side = 2.35 N m²/C