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2 years ago

Density is a derived unit of mass / volume.

Chemistry

1 answer:

lapo4ka [179]2 years ago

6 0

Answer:

1kg/L

Explanation:

1.) convert grams to kilograms

1000g÷1000=1kg

2.)use formula to find density

$density = \frac{mass}{volume}$

= 1kg/1.0L

=1kg/L

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How many hydrogen molecules are in 1.2 moles of hydrogen?

nalin [4]

Answer:

7.22 x 10²³molecules

Explanation:

Given parameters:

Number of moles of hydrogen = 1.2moles

Unknown:

Number of molecules of hydrogen = ?

Solution:

From the concept of moles, a mole of a substance contains the Avogadro's number of particles.

1 mole of a substance = 6.02 x 10²³ molecules;

So; 1.2 moles of hydrogen = 1.2 x 6.02 x 10²³ molecules;

= 7.22 x 10²³molecules

6 0

3 years ago

Select the answer which shows the correct order, slowest to fastest, of the relative rate of diffusion of the gases.

IrinaK [193]

Diffusion is the process of a substance spreading out to evenly fill its container or environment. Rate of diffusion of a gas is inversely proportional to the molar mass of the gas.

$Rate of diffusion \propto \frac{1}{Molar mass}$

Lighter(lower) the molar mass of the gas , faster will be its rate of diffusion and heavier (higher) the molar mass of the gas , slower will be its rate of diffusion.

We have to arrange the given gases from slowest rate of diffusion to fastest rate of diffusion that means we need to arrange gases from higher molar mass to lower molar mass.

Molar mass of given gases are :

Cl = 35.5 g/mol

Xe = 131.29 g/mol

He = 4.00 g/mol

N = 14.00 g/mol

So correct order for slowest rate of diffusion (highest molar mass) to fastest rate of diffusion (lowest molar mass) is :

Xe , Cl , N , He

Xe having the highest molar mass will have the slowest rate of diffusion and He with lowest molar mass will have the fastest rate of diffusion, so option 'c' is correct.

Note : Slowest rate of diffusion = High Molar Mass

Fastest rate of diffusion = Low Molar Mass

7 0

4 years ago

The rate of disappearance of HBr in the gas phase reaction 2 HBr(g) → H2(g) + Br2(g) is 0.140 M s-1 at 150°C. The rate of appear

djverab [1.8K]

Answer: The rate of appearance of $Br_2$ is $0.0700Ms^{-1}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$2HBr(g)\rightarrow H_2(g)+Br(g)$

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate in terms of disappearance of HBr = $-\frac{1d[HBr]}{2dt}Rate in terms of appearance of [tex]H_2$ = $\frac{1d[H_2]}{dt}$

Rate in terms of appearance of $Br_2$ = $\frac{1d[Br_2]}{dt}$

$-\frac{1d[HBr]}{2dt}=\frac{d[H_2]}{dt}=\frac{d[Br_2]}{dt}$

Given :

$-\frac{1d[HBr]}{dt}=0.140Ms^{-1}$

The rate of appearance of $Br_2$ ;

$\frac{1d[Br_2]}{dt}=-\frac{1d[HBr]}{2dt}=\frac{1}{2}\times 0.140=0.0700Ms^{-1}$

Thus rate of appearance of $Br_2$ is $0.0700Ms^{-1}$

6 0

3 years ago

Which statement best describes chemical properties of matter? Chemical properties, such as density, must be observed when a subs

alisha [4.7K]

Chemical properties of matter can only be observed and measured by performing a chemical change.
- Density and boiling are not chemical changes.
- This leaves reactivity and combustion. Reactivity does not need to be observed at STP so the statement is wrong.

Combustion is the best answer.

6 0

4 years ago

Read 2 more answers

A sample of O2(g) is placed in an otherwise empty, rigid container at 4224 K at an initial pressure of 4.97 atm, where it decomp

frutty [35]

Answer:

The value of $K_p$ at 4224 K is 314.23.