Answer: (a) +/- 7.5° (b) +/- 3.75°
Explanation:
See attachment
The air leaving through the balloon's mouth pulls the balloon in the same direction as the exiting air, so the balloon experiences a net force. All air surrounding the balloon pushes the balloon forward.
Answer:
D. To interpret the possible meaning of the data
The friction force f = 10000 N
The heat transfer Q = 1.7936 KJ
<u>Explanation:</u>
Given data:
Surface area of Piston = 1 
Volume of saturated water vapor = 100 K Pa
Steam volume = 0.05 
Using the table of steam at 100 K pa
Steam density = 0.590 Kg/
Specific heat
= 2.0267 KJ/Kg K
Mass of vapor = S × V
m = 0.590 × 0.05
m = 0.0295 Kg
Solution:
a) The friction force is calculated
Friction force = In the given situation, the force need to stuck the piston.
= pressure inside the cylinder × piston area
= 100 ×
× 0.1
f = 10000 N
b) To calculate heat transfer.
Heat transfer = Heat needs drop temperatures 30°C.

Q = 0.0295 × 2.0267 ×
× 30
Q = 1.7936 KJ
Answer:
shear plane angle Ф = 26.28°
shear strain 2.20
Explanation:
given data
angle = 16°
chip thickness t1 = 0.32 mm
cut yields chip thickness t2 = 0.72 mm
solution
we get here first chip thickness ratio that is
chip thickness ratio =
................. 1
put here value
chip thickness ratio =
chip thickness ratio r = 0.45
so here shear angle will be Ф
tan Ф =
............2
tan Ф =
tan Ф = 0.4938
Ф = 26.28°
and
now we get shear strain that is
shear strain r = cot Ф + tan (Ф - α ) ................3
shear strain r = cot(26.28) + tan (26.28 - 16 )
shear strain r = 2.20