Answer: the answer for the question is a
Explanation:
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Answer:
Refrigerant R-134a is to be cooled by waterin a condenser.The refrigerant enters thecondenser with a mass flow rate of 6 kg/minat 1 MPa and 70 C and exits at 35 C. The cool-ing water enters at 300 kPa and 15 C andleaves at 25 C. Neglecting pressure drops,determine a) the required mass flow rate ofthe cooling water, and b) the heat transferrate from the refrigerant to the water.SolutionFirst consider the condenser as the control volume. The process is steady,adiabatic and no work is done. Thus over any time intervalΔt,ΔEΔt=0and thusXin˙E=Xout˙Ewhere˙E=˙m h+12V2+gz650:351 Thermodynamics·Prof. Doyle Knight37
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I only know this
sorry for errors
Answer:
C. exactly vertical
Explanation:
"Plumb" means "exactly vertical."
Answer:
1.8 mm
Explanation:
given data
thick = 2.5 mm
flux = 1 × 
kg/m²
high pressure surface is 2 kg/m³
solution
we use fick first law for steady state diffusion
J = D × 
..........1
we take here Ca to point which concentration of nitrogen is 2 kg/m³
so we solve Xb
Xb = Xa + D × 
assume Xa = 0 at surface
Xb = 0 + ( 12 × 
) × 
Xb = 1.8 × 
Xb = 1.8 mm
