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enyata [817]
3 years ago
15

Florida's progressive DUI laws take ______ into account.

Engineering
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:

Permanent felony conviction on your criminal record.

Financial restitution if DUI involves an accident, property damage or personal injury

Up to 50 hours community service or fee of $10 per hour of service.

Minimum fine of upto $1000 or $2000, that is if your blood alcohol level was 0.15%  or more than this, or you were driving with a minor in the vehicle.

Imprisonment of upto 9 months, if the blood alcohol level was over 0.15% or idf the DUI  resulted in ana accident or crash, jail time is increased to one year.

Mandatory imprisonment for not less than 10 days if your second DUI conviction occurs within 5 years of the date of the prior DUI conviction.

180 days to one year probation.

Maximum of 5 years driver's license revocation.

Up to 30 days impoundment of vehicle.

Ignition interlock device.

Criminal record stating adjudication of guilt.

Explanation:

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vodka [1.7K]

Answer:

(⌐■-■) (⌐■-■) (⌐■-■) (⌐■-■)

5 0
3 years ago
Answer back to question for la ,lot points
Lerok [7]

Answer:

yes

Explanation:

yes

5 0
3 years ago
When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the str
Murljashka [212]

The question is incomplete. The complete question is :

The solid rod shown is fixed to a wall, and a torque T = 85N?m is applied to the end of the rod. The diameter of the rod is 46mm .

When the rod is circular, radial lines remain straight and sections perpendicular to the axis do not warp. In this case, the strains vary linearly along radial lines. Within the proportional limit, the stress also varies linearly along radial lines. If point A is located 12 mm from the center of the rod, what is the magnitude of the shear stress at that point?

Solution :

Given data :

Diameter of the rod : 46 mm

Torque, T = 85 Nm

The polar moment of inertia of the shaft is given by :

$J=\frac{\pi}{32}d^4$

$J=\frac{\pi}{32}\times (46)^4$

J = 207.6 mm^4

So the shear stress at point  A is :

$\tau_A =\frac{Tc_A}{J}$

$\tau_A =\frac{85 \times 10^3\times 12 }{207.6}$

$\tau_A = 4913.29 \ MPa$

Therefore, the magnitude of the shear stress at point A is 4913.29 MPa.

3 0
3 years ago
ممكن الحل ............
Roman55 [17]

Answer:

i dont understand

Explanation:

4 0
4 years ago
Anything that is made to meet a need or desire is?
slavikrds [6]

Answer:

I think it is process or technology

7 0
3 years ago
Read 2 more answers
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