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enyata [817]
3 years ago
15

Florida's progressive DUI laws take ______ into account.

Engineering
1 answer:
xz_007 [3.2K]3 years ago
8 0

Answer:

Permanent felony conviction on your criminal record.

Financial restitution if DUI involves an accident, property damage or personal injury

Up to 50 hours community service or fee of $10 per hour of service.

Minimum fine of upto $1000 or $2000, that is if your blood alcohol level was 0.15%  or more than this, or you were driving with a minor in the vehicle.

Imprisonment of upto 9 months, if the blood alcohol level was over 0.15% or idf the DUI  resulted in ana accident or crash, jail time is increased to one year.

Mandatory imprisonment for not less than 10 days if your second DUI conviction occurs within 5 years of the date of the prior DUI conviction.

180 days to one year probation.

Maximum of 5 years driver's license revocation.

Up to 30 days impoundment of vehicle.

Ignition interlock device.

Criminal record stating adjudication of guilt.

Explanation:

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Answer:

The net energy transfer from the student's body during the 20-min ride to school is 139.164 BTU.

Explanation:

From Heat Transfer we determine that heat transfer rate due to electromagnetic radiation (\dot Q), measured in BTU per hour, is represented by this formula:

\dot Q = \epsilon\cdot A\cdot \sigma \cdot (T_{s}^{4}-T_{b}^{4}) (1)

Where:

\epsilon - Emissivity, dimensionless.

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\sigma - Stefan-Boltzmann constant, measured in BTU per hour-square feet-quartic Rankine.

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T_{b} - Temperature of the bus, measured in Rankine.

If we know that \epsilon = 0.90, A = 16.188\,ft^{2}, \sigma = 1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}}, T_{s} = 554.07\,R and T_{b} = 527.67\,R, then the heat transfer rate due to electromagnetic radiation is:

\dot Q = (0.90)\cdot (16.188\,ft^{2})\cdot \left(1.714\times 10^{-9}\,\frac{BTU}{h\cdot ft^{2}\cdot R^{4}} \right)\cdot [(554.07\,R)^{4}-(527.67\,R)^{4}]

\dot Q = 417.492\,\frac{BTU}{h}

Under the consideration of steady heat transfer we find that the net energy transfer from the student's body during the 20 min-ride to school is:

Q = \dot Q \cdot \Delta t (2)

Where \Delta t is the heat transfer time, measured in hours.

If we know that \dot Q = 417.492\,\frac{BTU}{h} and \Delta t = \frac{1}{3}\,h, then the net energy transfer is:

Q = \left(417.492\,\frac{BTU}{h} \right)\cdot \left(\frac{1}{3}\,h \right)

Q = 139.164\,BTU

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