Force equals mass*acceleration
F = ma

Given m = 54.87 kg, a = 9.8 m/s^2

F = (54.87)(9.8)
F = 537.726
F = 538 N

A force of al least 538 Newtons is required to move the object.

7 0

2 years ago

A resistor is made out of a long wire having a length L. Each end of the wire is attached to a termina of a battery providing a

Len [333]

Answer:

B) 2I

Explanation:

The equation that relates voltage, current and resistance is V=RI.

The equation for the resistance of a material in terms of its resistivity, length and cross-sectional area is $R=\frac{\rho L}{A}$

In this case, the length is divided by 2 while keeping its resistivity (since it's the same material) and area, which means the resistance gets divided by 2. Then, looking at the equation I=V/R and keeping V constant, one deduces that since the resistance now is half than before then current now must be twice as before.

This is all intuitive in fact, cuting a homogeneous resistor in half and leaving the rest of the variables constant makes twice as easy for the electrons to cross the conductor, thus twice the current (one has to know that all the variables involved behave linearly, as the equations show).

8 0

2 years ago

Jonathan must lift a 3000n rock using a lever. jonathan uses 300n of force to push down on the lever to move the rock. what is t

-Dominant- [34]

The load is the weight of the rock that Jonathan lifts:
$L=3000 N$
The effort instead is the force applied in input to the lever in order to lift the rock:
$E=300 N$

So, the ratio between load and effort for this exercise is
$\frac{L}{E}= \frac{3000 N}{300 N}=10$
So, the ratio is 10:1.

3 0

2 years ago

A 0.10 kg ball of dough is thrown straight up into the air with an initial speed of 15 m/s.

Reptile [31]

<span>Mass of the ball is m = 0.10kg Initial speed of the Ball v = 15m/s a. When the ball is at maximum height the velocity is 0 Momentum of ball = mass x velocity Momentum = 0.10kg x 0 = 0 b. Getting the maximum height, Using the conservation of energy equation KEinitial = mgh 1/2mVin^2 = mgh => h = v^2/2g h = 15^2/2x9.8 = 11.48m => Half Height h = 5.96m Applying the conservation of energy equation at halfway V^2 = 2gh V = square root of (2x9.8x5.96) => V = square root of (116.816) So the velocity at the half way V = 10.81 m/s Momentum M = m x V => M = 0.10 x 10.81 => M = 1.081kg-m/s</span>

6 0

3 years ago