1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dafna1 [17]
3 years ago
8

If you are six feet tall how far back from a 3 foot mirror do you have to stand in order to see yourself completely?

Physics
1 answer:
OverLord2011 [107]3 years ago
7 0

Answer:

you would have to stand 6 ft back

Explanation:

You might be interested in
55 Points ££<br>which state of matter can undergo three types of thermal expansion​
bija089 [108]

Answer:

The three types of thermal expansions are Linear expansion , Superficial expansion and Cubical expansion

7 0
3 years ago
Read 2 more answers
when an object is placed near a concave mirror, at what position does it forms a magnified and erect image.​
alexira [117]

Answer:

Between the principal focus and the pole of the mirror

4 0
3 years ago
What type of issue does the effects manufacturer need
SOVA2 [1]

Answer:

A) Availability

Explanation:

Right on Edge 2021

4 0
3 years ago
Genes are organized on matching pairs of _______.
natta225 [31]

Answer:

homologous chromosomes

Explanation:

6 0
3 years ago
A projectile is launched straight up from a height of 960 feet with an initial velocity of 64 ft/sec. Its height at time t is h(
Natasha2012 [34]

Answer:

a) t=2s

b) h_{max}=1024ft

c) v_{y}=-256ft/s

Explanation:

From the exercise we know the initial velocity of the projectile and its initial height

v_{y}=64ft/s\\h_{o}=960ft\\g=-32ft/s^2

To find what time does it take to reach maximum height we need to find how high will it go

b) We can calculate its initial height using the following formula

Knowing that its velocity is zero at its maximum height

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

0=(64ft/s)^2-2(32ft/s^2)(y-960ft)

y=\frac{-(64ft/s)^2-2(32ft/s^2)(960ft)}{-2(32ft/s^2)}=1024ft

So, the projectile goes 1024 ft high

a) From the equation of height we calculate how long does it take to reach maximum point

h=-16t^2+64t+960

1024=-16t^2+64t+960

0=-16t^2+64t-64

Solving the quadratic equation

t=\frac{-b±\sqrt{b^{2}-4ac}}{2a}

a=-16\\b=64\\c=-64

t=2s

So, the projectile reach maximum point at t=2s

c) We can calculate the final velocity by using the following formula:

v_{y}^{2}=v_{o}^{2}+2g(y-y_{o})

v_{y}=±\sqrt{(64ft/s)^{2}-2(32ft/s^2)(-960ft)}=±256ft/s

Since the projectile is going down the velocity at the instant it reaches the ground is:

v=-256ft/s

5 0
3 years ago
Other questions:
  • Select the best terms from the drop-down menus that fit the nuclear medicine descriptions.
    9·2 answers
  • How did Rutherford's experiments demonstrate that Thomson's model of the atom was incorrect?
    10·2 answers
  • ____ are solid while lines stretching across one or more lanes in the same direction, indicating the proper place to come to a s
    7·1 answer
  • Most geologists accept radiometric dating techniques as valid because
    10·2 answers
  • When different resistors are connected in parallel across an ideal battery, we can be certain that: a) their equivalent resistan
    11·1 answer
  • What effects does the conductor have on the potential field?
    10·1 answer
  • a car is rolling backward when it hits the gas. after 8.25 s it is moving forward at 8.62m/s, and is 12.9m to the right of its s
    15·2 answers
  • Given the wave function: Y(x,t) = 5sin27(0.2x - 3t); (x = meters, t = sec.): What are the amplitude, frequency, wavelength, angu
    15·1 answer
  • Calculate the velocity of a car that travels 581 kilometers notheast in 3.5 hours?
    11·1 answer
  • The power of a bulb is 100 watt .what does it mean​
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!