Answer:
- The gravitational force by the Earth on the object, and by the object on the Earth is
- = 6.674×10−11 m3⋅kg−1⋅s−2 × 6 × 10^24 kg × 44.5 kg/(6.4 × 10^6 m)²
<u>Please note that the ration between the gravitation force 435 and the mass 44.5</u>
- should be gravitational acceleration
- I attribute the discrepancy between 9.78 and the usual 9.81 to rounding off in the
- Earth's weight and radius.
The mass of the Moon is M / 81.3.
The radius of the Moon is R × 0.27.
The gravitational force on the moon would be
G(M/81.3)m/(R×0.27)² = 0.17×GMm/R²
The gravitational force on the moon is smaller by the factor of about 0.17.
You divide 120 from 950 and that's the number of hours, 7.9
The reason for that is that P-waves (primary waves) travel faster than S-waves (secondary waves).
If we call
the speed of the primary waves and
the speed of the secondary waves, and we call
the distance of the seismogram from the epicenter, we can write the time the two waves take to reach the seismogram as
So the lag time between the arrival of the P-waves and of the S-waves is
We see that this lag time is proportional to the distance S, therefore the larger the distance, the greater the lag time.
Explanation:
Initially, two balls of the same shape and size have charges of +8 and-2. The balls are brought together, allowed to touch, and then separated.
When they are touched, the total charge is evenly distributed among the whole surface and they behaves as if it is a single piece. Net charge at this point is +8-2=6 C. When they are separated, each ball will have a charge of 6/2 = 3 C.
Answer:
Decreases the time period of revolution
Explanation:
The time period of Cygnus X-1 orbiting a massive star is 5.6 days.
The orbital velocity of a planet is given by the formula,
v = √[GM/(R + h)]
In the case of rotational motion, v = (R +h)ω
ω = √[GM/(R + h)] /(R +h)
Where 'ω' is the angular velocity of the planet
The time period of rotational motion is,
T = 2π/ω
By substitution,
<em>T = 2π(R +h)√[(R + h)/GM] </em>
Hence, from the above equation, if the mass of the star is greater, the gravitational force between them is greater. This would reduce the time period of revolution of the planet.
