) Continuing on Problem 1, assume a strain gage was bonded to the cylinder wall surface in the direction of the axial strain. Th
1 answer:
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Answer:
<em>The frequency changes by a factor of 0.27.</em>
<em></em>
Explanation:
The frequency of an object with mass m attached to a spring is given as
=
where is the frequency
k is the spring constant of the spring
m is the mass of the substance on the spring.
If the mass of the system is increased by 14 means the new frequency becomes
=
simplifying, we have
=
=
if we divide this final frequency by the original frequency, we'll have
==> ÷
==> x
==> 1/3.742 = <em>0.27</em>
Answer:
minimum length of runway is needed for take off 243.16 m
Explanation:
Given the data in the question;
mass of glider = 700 kg
Resisting force = 3700 N one one glider
Total resisting force on both glider = 2 × 3700 N = 7400 N
maximum allowed tension = 12000 N
from the image below, as we consider both gliders as a system
Equation force in x-direction
2ma = T -f
a = T-f / 2m
we substitute
a = (12000 - 7400 ) / (2 × 700 )
a = 4600/1400
a = 3.29 m/s²
Now, let Vf be the final speed and Ui = 0 ( as starts from rest )
Vf² = Ui² + 2as
solve for s
Vf² = 0 + 2as
2as = Vf²
s = Vf² / 2a
given that take of speed for the gliders and the plane is 40 m/s
we substitute
s = (40)² / 2×3.29
s = 1600 / 6.58
s = 243.16 m
Therefore, minimum length of runway is needed for take off 243.16 m
