Answer:
Option C, Intrapleural pressure is less than intrapulmonary pressure
Explanation:
During inspiration, the air enters the lungs due to lower pressure in the intrapulmonary or intra-alveolar than the atmospheric pressure. During quite respiration, the intrapulmonary pressure reduces to a pressure that is 3 mm Hg lower than that of atmospheric pressure. During quiet expiration, the intrapulmonary pressure rises up to a pressure that is 3 mm Hg higher than that of atmospheric pressure. This leads to lack of air in the intrapleural space thereby producing intrapleural pressure which is lesser than that of intrapulmonary pressure.
This difference in pressure (i.e higher pressure with in the lungs than the atmosphere) causes lungs to remain attached to the chest wall and hence looks inflated.
Hence, option C is correct
The answer to this question would be soft agar plate.
The semisolid medium tube is mostly used for containing the specimen. It is hard to examine semisolid medium since the bacteria can grow in the upper part, middle part or even the lower part of the medium. In agar plate, the bacteria always growth in the upper part so it is easier to count the bacteria.
But semisolid can give some more information in determining whether the bacteria is anaerobic by looking for bubble inside the medium. Anaerobic bacteria can do fermentation that will produce air.
Answer:
The correct answer is option D which is release of water from the vacuoles.
Explanation:
The difference in second plant from the first one is rigidity. Second one is wilted and not rigid. This is due to the release of water from the vacuoles in the cell of plants.
Vacuoles are present in the center of plant cell. They are usually filled with water and provide structural support to the cell.
In the absence of water filled vacuoles, plants shoots are wilted as in case of second plant.
Examples of bacteriophages are: 1) Temperate phages (mu and lambda) 2) Filamentous and spherical phages , both having ssDNA (single stranded DNA)
Pyruvic acid binds with Coenzyme A (CoA) to form acetyle CoA. The acetyle CoA begins the Kreb Cycle.
