HELP PLEASE!!!!!!!!!!!!!!!

Fill in the coefficients that will balance the following reaction a0h2so4 + a1koh → a2k2so4 + a3hoh

Anuta_ua [19.1K]

A0 = 1
a1 = 2
a2 = 1
a3 = 2

This can be solved by guessing and checking and making sure that all atoms on the left side are accounted for on the right side. Both sides must have the same amount of atoms or the balancing is not correct.

7 0

3 years ago

Read 2 more answers

At 298 K, what is the Gibbs free energy change (ΔG) for the following reaction?

9966 [12]

Answer:

(a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

Explanation:

Given that,

Temperature = 298 K

Suppose, density of graphite is 2.25 g/cm³ and density of diamond is 3.51 g/cm³.

$\Delta H\ for\ diamond = 1.897 kJ/mol$

$\Delta H\ for\ graphite = 0 kJ/mol$

$\Delta S\ for\ diamond = 2.38 J/(K mol)$

$\Delta S\ for\ graphite = 5.73 J/(K mol)$

(a) We need to calculate the value of $\Delta G$ for diamond

Using formula of Gibbs free energy change

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G= (1897-0)-298\times(2.38-5.73)$

$\Delta G=2895.3$

$\Delta G=2.895\ kJ$

The Gibbs free energy change is positive.

(b). When it is compressed isothermally from 1 atm to 1000 atm

We need to calculate the change of Gibbs free energy of diamond

Using formula of gibbs free energy

$\Delta S=V\times\Delta P$

$\Delta S=\dfrac{m}{\rho}\times\Delta P$

Put the value into the formula

$\Delta S=\dfrac{12\times10^{-6}}{3.51}\times999\times10130$

$\Delta S=34.59\ J/mole$

(c). Assuming that graphite and diamond are incompressible

We need to calculate the pressure

Using formula of Gibbs free energy

$\beta= \Delta G_{g}+\Delta G+\Delta G_{d}$

$\beta=V(-\Delta P_{g})+\Delta G+V\Delta P_{d}$

$\beta=\Delta P(V_{d}-V_{g})+\Delta G$

Put the value into the formula

$0=\Delta P(\dfrac{12\times10^{-6}}{3.51}-\dfrac{12\times10^{-6}}{2.25})\times10130+2895.3$

$0=-0.0194\Delta P+2895.3$

$\Delta P=\dfrac{2895.3}{0.0194}$

$\Delta P=14924\ atm$

(d). Here, $C_{p}=0$

So, The value of $\Delta H$ and $\Delta S$ at 900 k will be equal at 298 K

We need to calculate the Gibbs free energy of diamond relative to graphite

Using formula of Gibbs free energy

$\Delta G=\Delta H-T\Delta S$

Put the value into the formula

$\Delta G=(1897-0)-900\times(2.38-5.73)$

$\Delta G=4912\ J$

Hence, (a). The Gibbs free energy change is 2.895 kJ and its positive.

(b). The Gibbs free energy change is 34.59 J/mole

(c). The pressure is 14924 atm.

(d). The Gibbs free energy of diamond relative to graphite is 4912 J.

7 0

2 years ago

Determine the number of atom in 5.0 moles in SI

Alex

Answer: 3.01 x 10^24 atoms

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

So, 1 mole of SI = 6.02 x 10^23 atoms

5.0 moles = Z atoms

To get the value of Z, cross multiply:

(Z atoms x 1 mole) = (6.02 x 10^23 atoms x 5.0 moles)

Z atoms•1 mole = 30.1 x 10^23 atoms•moles

Divide both sides by 1 mole

Z atoms•1 mole / 1 mole = 30.1 x 10^23 atoms•moles / 1 mole

Z = 30.1 x 10^23 atoms

[Place Z in standard form

So, Z = 3.01 x 10^24 atoms]

Thus, there are 3.01 x 10^24 atoms in 5.0 moles in SI

5 0

2 years ago

When scientists create a representation of a complex process, they are

Burka [1]

Answer:

d making models.

Explanation:

When scientists create a representation of a complex process, they are inferring that they are making models.

A model is an abstraction of the real world or a complex process. Models are very useful in developing solutions to processes that are not easily simplified.

The models allow a part of a body to be simply studied.
Through this simple abstraction, extrapolations to other parts of the system can be deduced.
This can give very useful insights into the other parts of the system.
The heterogeneity of complex processes is a huge limitation to understanding them.
A homogenous part can be modelled and used to understand the system.

5 0

3 years ago

For a single H2 molecule, H2 → 2H, the dissociation energy is 4.52 eV. How much energy would have to be put in (in kJ) to dissoc

grandymaker [24]

Answer: 7.2418 x 10^-19 joules

Explanation:

1 eV equals 1.602 x 10^-19 joules

Then 4.52eV will be multiplied by the above value to give 7.2418 x 10^-19 joules which is the energy required to dissociate the hydrogen molecule

6 0

3 years ago