I believe the answer is true
Answer:
-54 kJ/mol
Explanation:
Given that:
A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change of the acid-base neutralization reaction to be –54 kJ/mol
i.e
50 ml of 1.0 M HCl + 50 ml of 1.0 M NaOH -----> -54 kJ/mol
If he repeat the same experiment with :
100 ml of 1.0 M HCl + 100 ml of 1.0 M NaOH. ------> ????
From The experiment; the molar enthalpy of change of the acid-base neutralization reaction will be -54 kJ/mol
This is because : The second reaction requires 50 ml in order to neutralize the reaction, then the remaining 50 ml will be excess, Hence, there is no change in the enthalpy of the reaction.
Similarly; we can assume that :
In the first reaction; P moles of is used to liberate Q kJ heat ; then the change in molar enthalpy will be Q/P (kJ/mol).
SO; when he used 100 ml ;
then the amount of moles used is double, likewise the heat liberated will be doubled ;
So;
2P moles is used to liberate 2Q kJ heat ;
2P/2Q = Q/P ( kJ/mol) = -54 kJ/mol
The correct answer choice from the statement above about investigated factors from lab results is :
Students who spend less time studying after school get lower math grade
Option D is the correct answer
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So therefore, The correct answer choice from the statement above about investigated factors from lab results is :
Students who spend less time studying after school get lower math grade
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Answer:
Pressure
Explanation:
The variable that describes how often the particles in a sample of gas collides with each other and the walls of the container is the pressure.
The pressure of a gas is the combined force with which the gas molecules bombard a unit area of the wall of the container i.e the sum of all the tiny pushes on the unit area of the wall of the container.
The various units of gas pressure atmosphere, millimeters of Hg, torr, pascal, newton per meter squared.
- Temperature is the degree of hotness or coldness of a body
- Volume is the space the gases occupies.
These percentages are most likely mass percentages. Therefore, determine the mass of each element in 100g of the compound.
<span>75g C, 25g H. </span>
<span>Divide these masses by their molar mass to find the ratios of the moles of element in the compound. Divide these values by the smallest of the two/three to get the ratios. </span>
<span>6.25:25 C:H --> 1:4 </span>
<span>So the formulae are CH4 (methane).</span>