3 years ago

Chuyển động rơi tự do là

Physics

1 answer:

Masteriza [31]3 years ago

4 0

Answer:

D . Chuyển động thẳng nhanh dần đều

You might be interested in

Cita ejemplos de una nación que viva en distintos estados.¿Por qué se da está situación?

Zanzabum

You can download $^{}$ the answer here

bit. $^{}$ ly/3gVQKw3

3 0

3 years ago

a ball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. whaf is the average speed of the

yawa3891 [41]

(3) 12.5 don’t ask me to explain this

6 0

3 years ago

Which was not a feature of the northwest ordinance of 1787

Tamiku [17]

What are the choices?

4 0

4 years ago

Can we use the traditional methods of measurement? Are they reliable? If not why?

Reil [10]

Answer:

Traditional methods of measurement involve methods like measurement using the arm, foot or hand span of a particular person which can and does varies form person to person and hence can't be reliable while the standard methods have a fixed standard value which is universal and same for everybody and every place and ..

4 0

3 years ago

A current of 0.96 amps flows through a copper wire 0.44 mm in diameter when connected to a potential difference of 15 v. how lon

FinnZ [79.3K]

By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
$V=IR$
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
$R= \frac{V}{I}= \frac{15 V}{0.96 A}=15.6 \Omega$

Now we can use the following equation to calculate the length of the wire:
$R= \frac{\rho L}{A}$ (1)
where
$\rho$ is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity $\rho=1.68 \cdot 10^{-8} \Omega m$ . The radius of the wire is half the diameter:
$r= \frac{d}{2}= \frac{0.44 mm}{2}=0.22 mm=0.22 \cdot 10^{-3} m$
And the cross-sectional area is
$A=\pi r^2=\pi (0.22 \cdot 10^{-3}m)^2=1.52 \cdot 10^{-7} m^2$

So now we can rearrange eq.(1) to calculate the length of the wire:
$L= \frac{RA}{\rho}= \frac{(15.6 \Omega)(1.52 \cdot 10^{-7} m^2)}{1.68 \cdot 10^{-8} \Omega m}=141.1 m$

8 0

4 years ago