As you know 30/45 = 6/9
So a = 9 makes the equation true
For this case we must find the product of the following expression:
We combine using the product rule for radicals:
![\sqrt [n] {a} * \sqrt [n] {b} = \sqrt [n] {ab}](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%7D%20%2A%20%5Csqrt%20%5Bn%5D%20%7Bb%7D%20%3D%20%5Csqrt%20%5Bn%5D%20%7Bab%7D)
So, we have:
We rewrite the 216 as
By definition of properties of powers and roots we have:
![\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a](https://tex.z-dn.net/?f=%5Csqrt%20%5Bn%5D%20%7Ba%20%5E%20n%7D%20%3D%20a%20%5E%20%7B%5Cfrac%20%7Bn%7D%20%7Bn%7D%7D%20%3D%20a)
Then, the expression is:
Answer:
Option D
Answer:
377 meals
Step-by-step explanation:
If you choose to have all three courses, then there are 6 choices for the first course, 8 for the second, and 5 for the last, making a total of 6*8*5=240 different possible meals.
If you choose two courses, then there are 3 options. You can pick appetizer and main meal, which would give you 6*8=48 possibilities. You can pick main meal and dessert, which would give you 8*5=40 possibilities. Finally you can pick appetizer and desert, which would give you 6*5=30 possibilities. In total these are 118 different possible meals with two courses.
Finally, you could choose 1 course, which would give you 6+8+5=19 different meals.
In total, this is 240+118+19=377 meals
