What kind of liquid promote corrosion

Calculate the molecular weights for NH3 and SF6.

nevsk [136]

Hi there,

NH3 has the weight of 17.03 grams, and SF6 has the weight of 146.06 grams

so in total, there is 163.09 grams

Hope this helps :P

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4 0

3 years ago

Which of the following has the most energy?

iren2701 [21]

Ultraviolet rays has the most energy

8 0

3 years ago

The noble gases are inert due to the fact that A. their valence shell is empty B. their valence shell is full C. their electrons

coldgirl [10]

Answer:

B) Their valence shell is full

Explanation:

In order to be classified as a noble gas, an element must have a complete octet/ a full shell of valence electrons, as shown in answer B.

A and C are just incorrect. Since noble gasses are very unstable, D is a true statement, but is isn't the correct answer as this does not explain why they are inert.

<h3>Hope this was helpful!</h3>

5 0

3 years ago

20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc

bezimeni [28]

Answer:

Concentration of the barium ions = $[Ba^{2+}] = 0.4654 M$

Concentration of the chloride ions = $[Cl^{-}]=0.9308 M$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride = 0.1355 M

$n=0.1355 M\times 0.04389 L=0.005947 mol$

$Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O$

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

$\frac{1}{2}\times 0.05947 mol=0.029735 mol$ barium hydroxide

Moles of barium hydroxide = 0.029735 mol

$Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)$

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

$=1\times 0.029735 mol= 0.029735 mol$

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL = 63.89 mL = 0.06389 L

Concentration of the barium ions = $[Ba^{2+}]$

$[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M$

$Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)$

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

$[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M$

8 0

3 years ago

If HCl is a 0.05 M solution and 50 mL is used to titrate the NaOH, what is the molarity of NaOH if the flask contains 100 mL?

Liono4ka [1.6K]

Answer:

Molarity of NaOH = 0.025 M

Explanation:

Given data:

Molarity of HCl = C₁ = 0.05 M

Volume of HCl = V₁= 50 mL

Molarity of NaOH = C₂=?

Volume of NaOH =V₂= 100 mL

Solution:

Formula:

C₁V₁ = C₂V₂

C₁ = Molarity of HCl

V₁ = Volume of HCl

C₂ = Molarity of NaOH

V₂ = Volume of NaOH

Now we will put the values:

C₁V₁ = C₂V₂

0.05 M × 50 mL = C₂ × 100 mL

2.5 M.mL =C₂ × 100 mL

C₂ = 2.5 M.mL /100 mL

C₂ = 0.025 M

7 0

3 years ago