What kind of liquid promote corrosion
1 answer:
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Answer:
Aluminum
Explanation:
Mass of = 1.68 g
Molar mass of = 143.32 g/mol
Thus,
From the reaction below:
3 moles of are produced when 1 mole of
undergoes reaction.
So,
1 mole of are produced when
mole of
undergoes reaction.
0.01172 mole of are produced when
mole of
undergoes reaction.
Thus, moles of = 0.0039 moles
Let the atomic mass of X = x g/mol
atomic mass of chlorine = 35.5 g/mol
Thus, Molar mass of = x + 3(35.5) g/mol = x + 106.5 g/mol
Moles = 0.0039 moles
Mass = 0.521 g
Thus, molar mass = Given mass/ Moles = 0.521 / 0.0039 = 133.5897 g/mol
So,
x + 106.5 = 133.5897
x = 27.0897 g/mol
This Atomic weight corresponds to Aluminum. Hence, X is aluminum.
The answer would be 0.8 mol of x left over....
AND THATS IS WHY...refer to the pic below...
See if it is clear enough...
AND THATS IS WHY...refer to the pic below...
See if it is clear enough...