Answer:
Part a)
V = 18.16 V
Part b)
![P_r = 345 Watt](https://tex.z-dn.net/?f=P_r%20%3D%20345%20Watt)
Part c)
P = 672 Watt
Part d)
V = 5.84 V
Part e)
![P_r = 345 Watt](https://tex.z-dn.net/?f=P_r%20%3D%20345%20Watt)
Explanation:
Part a)
When battery is in charging mode
then the potential difference at the terminal of the cell is more than its EMF and it is given as
![\Delta V = E + i r](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%20E%20%2B%20i%20r)
here we have
![E = 12 V](https://tex.z-dn.net/?f=E%20%3D%2012%20V)
![i = 56 A](https://tex.z-dn.net/?f=i%20%3D%2056%20A)
![r = 0.11](https://tex.z-dn.net/?f=r%20%3D%200.11)
now we have
![\Delta V = 12 + (0.11)(56) = 18.16 V](https://tex.z-dn.net/?f=%5CDelta%20V%20%3D%2012%20%2B%20%280.11%29%2856%29%20%3D%2018.16%20V)
Part b)
Rate of energy dissipation inside the battery is the energy across internal resistance
so it is given as
![P_r = i^2 r](https://tex.z-dn.net/?f=P_r%20%3D%20i%5E2%20r)
![P_r = 56^2 (0.11)](https://tex.z-dn.net/?f=P_r%20%3D%2056%5E2%20%280.11%29)
![P_r = 345 W](https://tex.z-dn.net/?f=P_r%20%3D%20345%20W)
Part c)
Rate of energy conversion into EMF is given as
![P_{emf} = i E](https://tex.z-dn.net/?f=P_%7Bemf%7D%20%3D%20i%20E)
![P_{emf} = (56)(12)](https://tex.z-dn.net/?f=P_%7Bemf%7D%20%3D%20%2856%29%2812%29)
![P_{emf} = 672 Watt](https://tex.z-dn.net/?f=P_%7Bemf%7D%20%3D%20672%20Watt)
Now battery is giving current to other circuit so now it is discharging
now we have
Part d)
![V = E - i r](https://tex.z-dn.net/?f=V%20%3D%20E%20-%20i%20r)
![V = 12 - (56)(0.11)](https://tex.z-dn.net/?f=V%20%3D%2012%20-%20%2856%29%280.11%29)
![V = 12 - 6.16 = 5.84 V](https://tex.z-dn.net/?f=V%20%3D%2012%20-%206.16%20%3D%205.84%20V)
Part e)
now the rate of energy dissipation is given as
![P_r = i^2 r](https://tex.z-dn.net/?f=P_r%20%3D%20i%5E2%20r)
![P_r = 56^2 (0.11)](https://tex.z-dn.net/?f=P_r%20%3D%2056%5E2%20%280.11%29)
![P_r = 345 W](https://tex.z-dn.net/?f=P_r%20%3D%20345%20W)
Answer:
r = 0.5 m
Explanation:
First we find the angular speed of the ball by using its period:
ω = θ/t
For the time period:
ω = angular speed = ?
θ = angular displacement = 2π rad
t = time period = 0.5 s
Therefore,
ω = 2π rad/0.5 s
ω = 12.56 rad/s
Now, for the radius:
v = rω
r = v/ω
where,
v = linear speed = 6.29 m/s
r = radius = ?
r = (6.29 m/s)/(12.56 rad/s)
<u>r = 0.5 m</u>
Answer:
3/7 ω
Explanation:
Initial momentum = final momentum
I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet
-Iω + 6Iω - 2Iω = 7I ωnet
3Iω = 7I ωnet
ωnet = 3/7 ω
The final angular velocity will be 3/7 ω counterclockwise.
From convection of magma under the earths crust makes the plates slowly move and as they move over time they build up potential energy from the different plates grinding against each other and after so long the plates will lose there grip on each other and release the potential energy they've been building up for so long as kinetic energy causing what you know as an earthquake hope this helps please give brainliest