A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?
Answer:

Step-by-step explanation:
Given:
A stuntman jumping off a 20-m-high building is modeled by the equation
-----------(1)
A high-speed camera is ready to making film between 15 m and 10 m above the ground
when the stuntman is 15m above the ground.
height
Put height value in equation 1





We know that the time is always positive, therefore 
when the stuntman is 10m above the ground.
height
Put height value in equation 1







Therefore ,time interval of camera film him is 
Answer:
x = -2 and y = 2
Step-by-step explanation:
The given equations are :
-5x-2y=6 ...(1)
3x+6y=6 ...(2)
Multiply equation (1) by 3. SO,
-15x-6y=18 ...(3)
Adding equation (2) and (3).
3x+6y-15x-6y = 6+18
-12x = 24
x = -2
Put the value of x in equation (1).
-5(-2)-2y=6
10-2y=6
4=2y
y = 2
So, the value of x is -2 and y is 2.
Your answer is 3/2 i know for a fact
It would be 1531600
How I did it
First I divided the percentage by 100. Example >> 0.6/100= 0.006
Then I took 2002 population >> 1522475 + 0.006 x 1522475 = 1531609.85