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2 years ago

Plizzz answer asap!!!!!

Mathematics

1 answer:

Anarel [89]2 years ago

3 0

The letters spell "ADD AND SUBTRACT LIKE TERMS ONLY".

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`h(t)=-5t^{2}+10t+3`

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Solve the equation for
t
t
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t
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−
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2
−
20
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10
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8 0

3 years ago

Write the equation of the line with the given slope through the given point<br> Slope = 6; (1, 2).

xz_007 [3.2K]

Answer:

Y=6x-4

Step-by-step explanation:

Y=mx+b

in this cace we have m- the slope

Y=6x+b

now we can plug in the coordinates to solve for b- the y intercept

(1,2) 1 being the x value, and 2 being the y value

2= 1·6+b

2=6+b

-4=b

now we take our previous equation, and add to it

Y=6x-4

4 0

3 years ago

Ryan is shopping for barrels of concrete. After looking at different stores, he decides to purchase them from Construction and U

Hitman42 [59]

Answer:

23$ for one bag

Step-by-step explanation:

46/2=23

5 0

2 years ago

Read 2 more answers

A car rental company offers two plans for renting a car. Plan A: $35 per day and $O.25 per mile. Plan B: $55 per day with free u

salantis [7]

The answer for this question is 90.25$

4 0

2 years ago

What is the solution to -x2 + 5x - 3

CaHeK987 [17]

The solution to the equation is $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Explanation:

Given that the equation is $-x^2+5x-3=0$

We need to determine the solution of the equation.

The solution of the equation can be determined using the quadratic formula.

The quadratic formula is given by

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Hence, from the equation, we have,

$a=-1,\:b=5,\:c=-3$

Substituting these values in the quadratic formula, we get,

$x=\frac{-5\pm \sqrt{5^2-4\left(-1\right)\left(-3\right)}}{2\left(-1\right)}$

Simplifying, we get,

$x=\frac{-5\pm \sqrt{25-12}}{-2}$

Simplifying the terms within the root, we get,

$x=\frac{-5\pm \sqrt{13}}{-2}$

Thus, the roots of the equation are $x=\frac{-5+ \sqrt{13}}{-2}$ and $x=\frac{-5- \sqrt{13}}{-2}$

Taking out the negative sign, we get,

$x=\frac{-(5- \sqrt{13})}{-2}$ and $x=\frac{-(5+ \sqrt{13})}{-2}$

Cancelling the negative sign, we get,

$x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

Thus, the solutions of the equation are $x=\frac{5-\sqrt{13}}{2}$ and $x=\frac{5+\sqrt{13}}{2}$

7 0

3 years ago

Plizzz answer asap!!!!!​

Plizzz answer asap!!!!!