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Westkost [7]
3 years ago
6

Plizzz answer asap!!!!!​

Mathematics
1 answer:
Anarel [89]3 years ago
3 0

The letters spell "ADD AND SUBTRACT LIKE TERMS ONLY".

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X 3) Find the product of 3 x 4 2/3 * O 18 3/4 O 12 6/3 or 14 o 71/2 (0) 14​
ladessa [460]

D. \: 14 \: ✅

Step-by-step explanation:

3 \times 4 \frac{2}{3}  \\  = 3 \times  \frac{14}{3}  \\ =   14

\circ \: \: { \underline{ \boxed{ \sf{ \color{green}{Happy\:learning.}}}}}∘

5 0
3 years ago
Read 2 more answers
The height of a stuntperson jumping off a building that is 20 m high is modeled by the equation h = 20 -57, where t is the time
cupoosta [38]

A stuntman jumping off a 20-m-high building is modeled by the equation h = 20 – 5t2, where t is the time in seconds. A high-speed camera is ready to film him between 15 m and 10 m above the ground. For which interval of time should the camera film him?

Answer:

1\leq t\geq \sqrt{2}

Step-by-step explanation:

Given:

A stuntman jumping off a 20-m-high building is modeled by the equation

h =20-5t^{2}-----------(1)

A high-speed camera is ready to making film between 15 m and 10 m above the ground

when the stuntman is 15m above the ground.

height h = 15m  

Put height value in equation 1

15 =20-5t^{2}

5t^{2} =20-15

5t^{2} =5

t^{2} =1

t =\pm1

We know that the time is always positive, therefore t=1

when the stuntman is 10m above the ground.

height h = 10m  

Put height value in equation 1

10 =20-5t^{2}

5t^{2} =20-10

5t^{2} =10

t^{2} =\frac{10}{5}

t^{2} =2

t=\pm\sqrt{2}

t=\sqrt{2}

Therefore ,time interval of camera film him is 1\leq t\geq \sqrt{2}

7 0
4 years ago
What is the solution of the system? Use elimination.<br><br> 3 (-5x-2y=6)<br> 3x+6y=6
Iteru [2.4K]

Answer:

x = -2 and y = 2

Step-by-step explanation:

The given equations are :

-5x-2y=6 ...(1)

3x+6y=6 ...(2)

Multiply equation (1) by 3. SO,

-15x-6y=18 ...(3)

Adding equation (2) and (3).

3x+6y-15x-6y = 6+18

-12x = 24

x = -2

Put the value of x in equation (1).

-5(-2)-2y=6

10-2y=6

4=2y

y = 2

So, the value of x is -2 and y is 2.

6 0
3 years ago
ABCD and PLMN are similar rectangles. Find the scale factor for turning rectangle ABCD into rectangle PLMN.
Usimov [2.4K]
Your answer is 3/2 i know for a fact
4 0
3 years ago
What was the population of south Australia closest to in 2003?
Brrunno [24]
It would be 1531600

How I did it
 First I divided the percentage by 100. Example >> 0.6/100= 0.006
  Then I took 2002 population >> 1522475 +  0.006  x  1522475 = 1531609.85
6 0
3 years ago
Read 2 more answers
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