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2 years ago

When do (object distance) is very large, what does the thin lens equation predict for the value of 1/f?

Physics

1 answer:

N76 [4]2 years ago

6 0

Answer:

1 / f = 1 / o + 1 / i

1 / image distance + 1 / object distance = 1 focal length

If the object distance is large the image will be at about the focal length

The value of 1 / f is fixed for any one particular lense

As the object distance decreases the image must increase

The above equation can also be written as

o i / (i + o) = f or i / (i / o + 1) = f

If for instance o was very large the image would be at the focal length

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3 years ago

Constant Acceleration Kinematics: Car A is traveling at 22.0 m/s and car B at 29.0 m/s. Car A is 300 m behind car B when the dri

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Answer:

The taken is $t_A = 19.0 \ s$

Explanation:

Frm the question we are told that

The speed of car A is $v_A = 22 \ m/s$

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The distance of car B from A is $d = 300 \ m$

The acceleration of car A is $a_A = 2.40 \ m/s^2$

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$d = v_A t_A + \frac{1}{2}a_A t_A^2 - 300$

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$d = 22t_A + \frac{1}{2} (2.40)^2 t_A^2 - 300$

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2 years ago

A 42.2 kg sled is pulled forward

zaharov [31]

The net force on the sledge is 31.64N.

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refer brainly.com/question/24557767

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