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Ilya [14]
3 years ago
7

If a wave's frequency doubles in the same medium, what are the other

Physics
1 answer:
natulia [17]3 years ago
5 0

Answer:

Wavelength divided in half and speed stays the same

Explanation:

We can use the equation that relates the frequency, the velocity and the wavelength:

f=\frac{v}{\lambda}

where f is the frequency, v is the velocity, and \lambda is the wavelength.

Since the wave is in this case always in the same medium, the velocity will not change.

and as we can wee from f=\frac{v}{\lambda} the frequency and the wavelength are Inversely proportional, this means that if the frequency increases, the the wavelength decreases.

In other words, if the frequency double, the wavelength does the opposite (is divided in half)

you can also see this if you multiply the equacion f=\frac{v}{\lambda} by 2:

2f=2(\frac{v}{\lambda} )\\

re arrenging the right side:

2f=\frac{v}{\frac{1}{2}\lambda }

for the frequency to double, the wavelength must be divided by 2.

the answer is

Wavelength divided in half and speed stays the same

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Arlecino [84]
67 is the answer . jen did
5 0
3 years ago
A police officer in hot pursuit of a criminal drives her car through an unbanked circular (horizontal) turn of radius 300 m at a
Mamont248 [21]

Answer:

The angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is <u>10°.</u>

Explanation:

Given:

Mass of the driver is, m=55\ kg

Radius of circular turn is, R=300\ m

Linear speed of the car is, v=22.2\ m/s

Since, the car makes a circular turn, the driver experiences a centripetal force radially inward towards the center of the circular turn. Also, the driver experiences a downward force due to her weight. Therefore, two forces act on the driver which are at right angles to each other.

The forces are:

1. Weight = mg=55\times 9.8=539\ N

2. Centripetal force, 'F', which is given as:

F=\frac{mv^2}{R}\\F=\frac{55\times (22.2)^2}{300}\\\\F=\frac{55\times 492.84}{300}\\\\F=\frac{27106.2}{300}=90.354\ N

Now, the angle of the net force acting on the driver with respect to the vertical is given by the tan ratio of the centripetal force (Horizontal force) and the weight (Vertical force) and is shown in the triangle below. Thus,

\tan \theta=\frac{90.354}{539}\\\tan \theta=0.1676\\\theta=\tan^{-1}(0.1676)=9.52\approx 10°

Therefore, the angle (relative to vertical) of the net force of the car seat on the officer to the nearest degree is 10°.

3 0
3 years ago
2. A liquid that is twice as dense as water is used in a barometer. With this barometer, atmospheric pressure would push the liq
Scrat [10]

Answer:

The reason why the height for the liquid is 5.18 m is because, for constant pressure, height is inversely proportional to density.

Explanation:

We know that pressure, P = ρgh where ρ = density of material, g = 9.8 m/s and h = height.

Since density of liquid = 2 × density of water = 2 × 1000 kg/m = 2000 kg/m³

Since atmospheric pressure = 101500 N/m²,

The height of liquid for this pressure is h = P/ρg = 101500/(2000 × 9.8) = 5.18 m

For the same pressure, the height for water is h = P/ρg = 101500/(1000 × 9.8) = 10.36 m

Since pressure = constant,

P = ρgh ⇒ P/ρg = h since P and g are constant, h ∝ 1/ρ

ρ₁h₁ = ρ₂h₂

So, the reason why the height for the liquid is 5.18 m is because, for constant pressure, height is inversely proportional to density.

8 0
3 years ago
A student places blocks on a 100cm long see-saw as shown/
Hunter-Best [27]

Answer:

Part 1)

\tau_1 = 5 \times (0.50) = 2.5 N m

Part 2)

\tau_2 = 14 \times (0.30) = 4.2 N m

Part 3)

\tau_3 = 1.4 N m

Part 4)

Since torque on right side is more so here it will turn and slip over it

Explanation:

As we know that the block A is placed at distance

d = 50 cm from the hinge at 70 cm mark

So torque due to weight of A is given as

\tau_1 = 5 \times (0.50) = 2.5 N m

the block B is placed at distance

d = 30 cm from the hinge at 70 cm mark

So torque due to weight of B is given as

\tau_2 = 14 \times (0.30) = 4.2 N m

Now torque due to weight of the scale is given as

\tau_3 = 7(0.20)

\tau_3 = 1.4 N m

now torque on left side of scale is given as

\tau_{left} = \tau_1 + \tau_3

\tau_{left} = 2.5 + 1.4 = 3.9 N m

Torque on right Side is given as

\tau_{right} = \tau_2 = 4.2 Nm

Since torque on right side is more so here it will turn and slip over it

8 0
3 years ago
Can someone please help me with this? <br>​
Sauron [17]

Divide 56 by 60 then x the answer by 6 then you get 5.6km which is your answer.

5 0
3 years ago
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