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Ilya [14]
3 years ago
7

If a wave's frequency doubles in the same medium, what are the other

Physics
1 answer:
natulia [17]3 years ago
5 0

Answer:

Wavelength divided in half and speed stays the same

Explanation:

We can use the equation that relates the frequency, the velocity and the wavelength:

f=\frac{v}{\lambda}

where f is the frequency, v is the velocity, and \lambda is the wavelength.

Since the wave is in this case always in the same medium, the velocity will not change.

and as we can wee from f=\frac{v}{\lambda} the frequency and the wavelength are Inversely proportional, this means that if the frequency increases, the the wavelength decreases.

In other words, if the frequency double, the wavelength does the opposite (is divided in half)

you can also see this if you multiply the equacion f=\frac{v}{\lambda} by 2:

2f=2(\frac{v}{\lambda} )\\

re arrenging the right side:

2f=\frac{v}{\frac{1}{2}\lambda }

for the frequency to double, the wavelength must be divided by 2.

the answer is

Wavelength divided in half and speed stays the same

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A force F of magnitude 2x^3 is applied to stop a particle moving with an initial velocity of v0. The particle travels from x=0 t
3241004551 [841]

Answer:

Explanation:

Given that

F=2x³

Work is given as

The range of x is from x=0 to x=D

W=-∫f(x)dx

Then,

W=-∫2x³dx from x=0 to x=D

W=- 2x⁴/4 from x=0 to x=D

W=-2(D⁴/4-0/4)

W=-D⁴/2

W=1/2D⁴

The correct answer is F

5 0
3 years ago
A 235.0 g metal block absorbs 2.44 × 103 J of heat to raise its temperature by 35 K. What is the specific heat of the metal? Sho
andrew-mc [135]
When an object absorbs an amount of energy equal to Q, its temperature raises by \Delta T following the formula
Q=m C_s \Delta T
where m is the mass of the object and C_s is the specific heat capacity of the material.

In our problem, we have Q=2.44 \cdot 10^3 J, m=235.0 g and \Delta T=35 K, so we can re-arrange the formula and substitute the numbers to find the specific heat capacity of the metal:
C_s =  \frac{Q}{m \Delta T}= \frac{2.44 \cdot 10^3 J}{(235.0 g)(35 K)}=0.297 J g^{-1} K^{-1}
3 0
3 years ago
An ocean wave has a wavelength of 10 m and a frequency of 4.0 Hz. What is the velocity of the
aleksandr82 [10.1K]

The velocity of the wave is 40 m/s

Explanation:

The relationship between the velocity of a wave and its frequency and wavelength is given by

v=f \lambda

where

v is the velocity

f is the frequency

\lambda is the wavelength

For the ocean wave in this problem, we have:

\lambda = 10 m (wavelength)

f = 4.0 Hz (frequency)

Therefore, its velocity is

v=(4.0)(10)=40 m/s

Learn more about waves:

brainly.com/question/5354733

brainly.com/question/9077368

#LearnwithBrainly

3 0
3 years ago
With what type of electromagnetic radiation would you observe:
Viefleur [7K]

Answer:

Green part of the visible spectrum.

X ray part of the electromagnetic spectrum.

Infrared part of the electromagnetic spectrum.

Explanation:

Wien's displacement law

\lambda_{max}=\frac{b}{T}

Where, b = Wien's displacement constant = 2.898×10⁻³ mK

T = Temperature in kelvin

\lambda_{max}=\frac{2.898\times 10^{-3}}{5800}\\\Rightarrow\lambda_{max}=0.499\times 10^{-6}=0.5\mu m=500\ nm

So, the wavelength would be of around the green part of the visible spectrum.

\lambda_{max}=\frac{2.898\times 10^{-3}}{1\times 10^6}\\\Rightarrow\lambda_{max}=2.898\times 10^{-9}=2.898\ nm

So, the wavelength would be of around the X ray part of the electromagnetic spectrum.

Human body temperature = 37°C = 37+273.15 = 310.15 K

\lambda_{max}=\frac{2.898\times 10^{-3}}{37+273.15}\\\Rightarrow\lambda_{max}=\frac{2.898\times 10^{-3}}{310.15}\\\Rightarrow\lambda_{max}=9.34\times 10^{-6}=934\ nm

So, the wavelength would be of around the Infrared part of the electromagnetic spectrum.

5 0
3 years ago
If I was to build a functioning Scale Model of a dam, what would I need?
anyanavicka [17]
You will need rocks brick and water.
8 0
3 years ago
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