1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ilya [14]
3 years ago
7

If a wave's frequency doubles in the same medium, what are the other

Physics
1 answer:
natulia [17]3 years ago
5 0

Answer:

Wavelength divided in half and speed stays the same

Explanation:

We can use the equation that relates the frequency, the velocity and the wavelength:

f=\frac{v}{\lambda}

where f is the frequency, v is the velocity, and \lambda is the wavelength.

Since the wave is in this case always in the same medium, the velocity will not change.

and as we can wee from f=\frac{v}{\lambda} the frequency and the wavelength are Inversely proportional, this means that if the frequency increases, the the wavelength decreases.

In other words, if the frequency double, the wavelength does the opposite (is divided in half)

you can also see this if you multiply the equacion f=\frac{v}{\lambda} by 2:

2f=2(\frac{v}{\lambda} )\\

re arrenging the right side:

2f=\frac{v}{\frac{1}{2}\lambda }

for the frequency to double, the wavelength must be divided by 2.

the answer is

Wavelength divided in half and speed stays the same

You might be interested in
A copper wire 1.0 meter long and with a mass of .0014 kilograms per meter vibrates in two segments when under a tension of 27 Ne
Furkat [3]

Answer:

the frequency of this mode of vibration is 138.87 Hz

Explanation:

Given;

length of the copper wire, L = 1 m

mass per unit length of the copper wire, μ = 0.0014 kg/m

tension on the wire, T = 27 N

number of segments, n = 2

The frequency of this mode of vibration is calculated as;

F_n = \frac{n}{2L} \sqrt{\frac{T}{\mu} } \\\\F_2 = \frac{2}{2\times 1} \sqrt{\frac{27}{0.0014} }\\\\F_2 = 138.87 \ Hz

Therefore, the frequency of this mode of vibration is 138.87 Hz

7 0
3 years ago
What is a literature review?<br>​
almond37 [142]

Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.

Explanation:

7 0
2 years ago
Two long, straight wires are parallel and 26 cm apart.
mezya [45]

Answer: 2.49×10^-3 N/m

Explanation: The force per unit length that two wires exerts on each other is defined by the formula below

F/L = (u×i1×i2) / (2πr)

Where F/L = force per meter

u = permeability of free space = 1.256×10^-6 mkg/s^2A^2

i1 = current on first wire = 57A

i2 = current on second wire = 57 A

r = distance between both wires = 26cm = 0.26m

By substituting the parameters, we have that

Force per meter = (1.256×10^-6×57×57)/ 2×3.142 ×0.26

= 4080.744×10^-6/ 1.634

= 4.080×10^-3 / 1.634

= 2.49×10^-3 N/m

5 0
3 years ago
The membrane that surrounds a certain type of living cell has a surface area of 7.1 x 10-9 m2 and a thickness of 1.5 x 10-8 m. A
hoa [83]

Answer:

Q = +1.4 pC

Explanation:

  • The capacitance of any capacitor, by definition, is as follows:
  •  C = \frac{Q}{V} (1)
  • Applying Gauss'Law and the definition of electric potential, it can be showed that the capacitance of a parallel-plate capacitor can be expressed as follows:
  •  C = \frac{\epsilon_{r}*\epsilon_{0} * A}{d} (2)
  • Where εr is the dielectric constant of the material that fills the space between the plates, A is the area of one of the plates, and d, is the separation between them.
  • Replacing by the givens in (2) we can find the value of the capacitance C, as follows:

       C = \frac{\ 4.4*8.85e-12C2/N*m2*7.1e-9m2}{1.5e-8m} = 18.4e-12 F = 18.4 pF

  • Replacing the values of C and V in (1), we can solve for Q, as follows:

       Q = C*V = 18.4e-12 F* 75.9e-3 V = 1.4e-12 C = +1.4 pC

  • As the outer surface is at a higher potential that the inside surface, the charge on it must be positive, and is equal to +1.4 pC.
7 0
3 years ago
Velocity of an object of mass 5 kg increases from 3 m/s to 7 m/s on applying a force continuously for 2 s. Find out the force ap
Alenkasestr [34]

Answer:

Force=10N

Velocity=13m/s

Explanation:

Given,

Mass = 5kg

initial velocity=3m/s

Final velocity=7m/s

Time=2s

Now acceleration= v-u/t

=7-3/2

=4/2

=2m/s²

So, acceleration=2m/s²

Now,

F=ma

=5*2

=10N

7 0
2 years ago
Other questions:
  • which of the following is an example of a compound machine. a. a bicycle chain. b. a coffee mug. c. a paper cutter
    13·1 answer
  • Joan purchased a large, tough cut of beef. To make the meat more tender what should she do
    10·1 answer
  • A 12 n cart is moving on a horizontal surface with a coefficient of kinetic friction of 0.20. what force of friction must be ove
    7·1 answer
  • When do cells use oxygen to release energy
    11·1 answer
  • Please help!!30 points and will give the brainliest answer for a clear explanation.I need it really fast. Thank you!
    11·1 answer
  • The sun, like all stars, releases energy through nuclear fusion. In this problem, you will find the total number of fusion react
    9·1 answer
  • What are the standard units of measurement for scientific experiments
    5·2 answers
  • What is the particles instantaneous speed at t=16 sec
    14·1 answer
  • How is solar impulse is different than conventional airplane
    13·1 answer
  • HELPPPPPPPPPPPPPPPPPPPPPPPPPP
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!