The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
U = m ΔT
U = Energy
= Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ = 1000 g / m³ (Dry air )
= 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1000 * 48
m = 48000 g
U = 1 * 48000 * 7
U = 336000 J
U = 336 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
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Answer:
Half as much as it was
Explanation:
According to Charles law
PV = k
P is the pressure
V is the volume
If PV= k, then P1V1= P2V2
P1 and P2 are the initial and final pressure respectively
V1 and V2 are the initial and final volume respectively
Given
V1 =11.2litres
P1 = 0.860atm
If the volume is doubled, V2 = 2(11.2) = 22.4litres
Get P2
P2 = P1V1/V2
P2 = 0.860×11.2/22.4
P2 = 0.860/2
P2 = P1/2 (since P1 =0.860)
P2 = 1/2 P1
Hence the pressure becomes halved if the volume is doubled
Answer:
See below
Explanation:
29 mile/hr * 5280 f/mile / 3600 s/hr = 42.53 ft/ sec
42.53 ft / sec / 12 feet = 3.54 cycles / sec = 3.54 Hz
for frequency I suppose....where is the referred to figure?
Answer:
Laser
Explanation:
A laser is not a form of wave.
The sound wave is series of rarefaction and compressions traveling through substance . and the waves travel through medium like solid , liquid , and gases