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LekaFEV [45]
3 years ago
13

A 4.5 kg box is being pulled by a girl using a string that makes an angle of 20° horizontal. Find the force of friction if the f

orce exerted on the string is 15 N and the coefficient of friction is 0.5.
Physics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

Fcoso-f =ma. F= ma 15 = 4.5 a then get acceleration. Fcoso- umg = ma then get friction

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What is force of attraction ?​
Otrada [13]

Answer

a force between two bodies, molecules, particles, or the like, that attracts each to the other. Gravity is the force of attraction between two bodies that have mass.

Explanation:

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Weight and mass are interchangeable terms. True or False
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Whta is the mechanical advantage when the effort force is 20 and the resistance force is 5
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Challenge! A marshmallow is dropped from a 5-meter high pedestrian bridge and 0.83 seconds later, it lands right on the head of
WINSTONCH [101]

a₀).  You know ...
         -- the object is dropped from 5 meters
             above the pavement;
         --  it falls for 0.83 second.

a₁).  Without being told, you assume ...
         -- there is no air anyplace where the marshmallow travels,
             so it free-falls, with no air resistance;
         -- the event is happening on Earth,
            where the acceleration of gravity is  9.81 m/s² .

b).  You need to find how much LESS than 5 meters
       the marshmallow falls in 0.83 second.
    
c).  You can use whatever equations you like.
       I'm going to use the equation for the distance an object falls in
       ' T ' seconds, in a place where the acceleration of gravity is ' G '.

d).  To see how this all goes together for the solution, keep reading:


The distance that an object falls in ' T ' seconds
when it's dropped from rest is

                                 (1/2 G) x (T²) .

On Earth, ' G ' is roughly  9.81 m/s², so in 0.83 seconds,
such an object would fall

                               (9.81 / 2) x (0.83)² = 3.38 meters .

It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was

                         (5.00 - 3.38)  =  1.62 meters

above the pavement.  That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.

7 0
3 years ago
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