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Lisa [10]
2 years ago
9

In a series lrc circuit, the frequency at which the circuit is at resonance is f0. If you double the resistance, the inductance,

the capacitance, and the voltage amplitude of the ac source, what is the new resonance frequency?.
Physics
1 answer:
taurus [48]2 years ago
6 0

When you double capacitance and inductance, the new resonance frequency becomes f/2.

  • Resonance frequency:

The resonance frequency of RLC series circuit, is the frequency at which the capacity reactance is equal to inductive reactance.

It can also be defined as the natural frequency of an object where it tends to vibrate at a higher amplitude.

Xc = Xl

which gives the value for resonance frequency:

f = \frac{1}{2\pi \sqrt{LC} }

where;

f is the resonance frequency

L is the inductance

C is the capacitance

When you double capacitance and inductance, the new resonance frequency becomes;

f' = \frac{1}{2\pi \sqrt{2L2C} }

f' = \frac{1}{2\pi \sqrt{4LC} }

f' = \frac{1}{\pi \sqrt{LC} }\frac{1}{2}

f' = \frac{1}{2} f

Thus from above,

When you double capacitance and inductance, the new resonance frequency becomes f/2.

Learn more about resonance frequency here:

<u>brainly.com/question/13040523</u>

#SPJ4

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