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LenKa [72]
3 years ago
9

Please help me with a physics question

Physics
1 answer:
Oliga [24]3 years ago
8 0

Answer:

I could swear I just answered this question  

Centripetal force is the force that keeps the yoyo going in a circle, if the string breaks, the yoyo would would fly off in a direction that is different to the point on the circle.

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A 12.0 V car battery is being used to power the headlights of a car. Each of the two headlights has a power rating of 37.7 Watts
marshall27 [118]

Answer:

3.921*10^19 electrons

Explanation:

To find the number of electron that trough the car battery you first calculate the current by using the following formula, which relates the power with the voltage:

P=IV          (1)

P: power of both headlights = 2(37.7W) = 75.4 W

I: current = ?

V: voltage of the battery = 12.0 V

You solve the equation (1) for I:

I=\frac{P}{V}=\frac{75.4W}{12.0V}=6.283A=6.238\frac{C}{s}

Next, you use the equivalence 1C = 6.241*10^18 electrons:

6.238\frac{C}{s}*\frac{6.241*10^{18}\ electrons}{1C}=3.921*10^{19}\ electrons/s

The number of electrons that cross the battery per second is 3.921*10^19 electrons

6 0
4 years ago
The doppler effect is the change in observed frequency due to
Serga [27]

Answer: relative motion between observer and the sound source.

Explanation: The Doppler effect states that when there is a relative motion between an observer and a sound source the frequency of sound perceived by the observer is different in frequency from the original from the source.

The mathematical back up for this claim is given below.

f' = (v+v') /(v-vs) × f

Where f' = observed frequency

v = speed of sound in air

v' = velocity of observer

vs = velocity of source

f = frequency of sound source.

From the formulae, it can be seen that a change in the value of the velocity of observer (v') and source (vs) produces different value of observed frequency (f').

Note, frequency of sound (f) is a constant.

4 0
4 years ago
A stone is dropped from a bridge 45 meters above the surface river. It takes the stone 4.6 seconds to reach the water surface. F
Hunter-Best [27]
The most interesting thing about this problem is that in order to use all of the given information, you need to ignore the laws of Physics, and never mind what the stone would really do if dropped from a real bridge in the real world.

Average velocity = (displacement) / (time for the displacement)

Displacement =
        Straight path from the start point to the finish point  =  45 meters down .
Time = 4.6 seconds

Average velocity  =  45/4.6 = <em>9.783 meters/second down</em>

==================================

In the real world, a dropped stone would only take  3.03  seconds
to fall 45 meters.

Alternatively, a stone that fell for  4.6 seconds from rest would fall
103.7 meters, with an average velocity of  22.5 meters/second down.

But we accepted the given information, and did the best we could do
with it.
7 0
3 years ago
Read 2 more answers
What do miles, kilometers, and light-years have in common?<br><br>​
Radda [10]

They are all units of measure of length

Explanation:

Length is a scalar quantity representing a distance between two points, and it can be expressed in different units.

The SI units of the length is the metre (m), which is defined as the length of the path travelled by light in vacuum during a time interval of 1/299,792,458 of a second.

A unit which is common used is a multiple of the meter, the kilometre (km) which corresponds to 1000 metres:

1 km = 1000 m

Another unit used in the UK system is the mile (mi), where the conversion factor between miles and metres is

1 mi = 1609.34 m

Finally, these units are not suitable to be used to measure astronomical distances - such as those between stars and galaxies. For this, another unit is used, which is the light-year (ly), which corresponds to the distance travelled by the light in a vacuum in one year, and its conversion factor to the metre is:

1 ly = 9.46\cdot 10^{15}ly

Learn more about distance here:

brainly.com/question/3969582

#LearnwithBrainly

6 0
3 years ago
Static charges can be applied to neutral objects by friction, induction or conduction. What do all of these methods utilize to c
kvv77 [185]

Answer:

B) electrons

Explanation:

When charge is transferred by friction, induction or conduction, the charge carriers are the electrons.

In fact, protons and neutrons are found within the nucleus of the atoms, so they are tightly bound and they cannot be easily gained/given off. On the contrary, electrons are found in the electron clouds around the nucleus, so atoms can more easily gain/lose electrons, which become free and can be passed by an object to another.

The three methods of charging are:

- Friction: by rubbing two objects together, electrons may be transferred from one to another

- Induction: by moving a charged object closer to a neutral object, opposite charges in the neutral object migrate towards the opposite ends of the object, and if the object is connected to the ground, the charges of one polarity leave the object, leaving the object charged

- Conduction: by putting a charged object in contact with a neutral object, electrons can be transferred from the charged object to the neutral one

5 0
3 years ago
Read 2 more answers
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