What is atom? give long answer
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Answer:
The empirical formula of a compound is Na2Cr2O7
Explanation:
Empirical formula is defined as the lowest ratio of elements present in any substance. In order to determine the empirical formula for a substance containing these elements we have to follow some steps.
1.In the first step, we have to divide the given mass of an element with its molecular mass to convert the mass to moles.
Similarly, the moles of Cr and O in that compound were calculated and found as 0.396 and 1.3875, respectively.
2. Then the next step is to determine the lowest moles and divide all the moles with that lowest mole. As here the lowest mole is 0.396. So on dividing the moles of Na, Cr and O with 0.396, we will obtain the ratio as 1:1:3.5.
3. As the ratio consists of a fractional number, we have to multiply it with the smallest possible integer to convert it to whole number. In this case, if we multiply it with 2 , we will get the ratio as 2:2:7.
Thus, the empirical formula for the compound can be written as Na2Cr2O7.
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Explanation:
AgNO₃+Na₃(PO₄) → Ag₃(PO₄) + NaNO₃
To balance this chemical equation, we can adopt a simple mathematical approach through which we can establish simple and solvable algebraic equations.
aAgNO₃ + bNa₃PO₄ → cAg₃PO₄ + dNaNO₃
a, b, c and d are the coefficients needed to balance the equation.
Conserving Ag: a = 3c
N: a = d
O: 2a + 4b = 4c + 2d
Na: 3b = d
P: b = c
let a = 1; d = 1
b =
c =
Multiplying through by 3:
a = 3, b = 1, c = 1 and d = 3
3AgNO₃ + Na₃PO₄ → Ag₃PO₄ + 3NaNO₃
Learn more:
Balanced equation brainly.com/question/5964324
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