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Ede4ka [16]
3 years ago
15

The mass of a single gold atom is 3.27×10-22 grams. How many gold atoms would there be in 43.2 milligrams of gold?

Chemistry
1 answer:
natima [27]3 years ago
3 0

There are 1.32 × 10²⁰ atoms in 43.2 mg of gold.

<em>Step 1</em>. Convert <em>grams of Au</em> to <em>moles of Au</em>

Moles of SF₆ = 0.0432 g Au × (1 mol Au/196.97 g Au) = 2.193 × 10⁻⁴ mol Au

<em>Step 2</em>. Convert <em>moles of Au</em> to <em>atoms of Au</em>.

Atoms of Au = 2.193 × 10⁻⁴ mol Au × (6.022 × 10²³ atoms Au /1 mol Au)

= 1.32 × 10²⁰ atoms Au

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How many moles of hexane must burn to form 18.4 mol of carbon dioxide
Talja [164]
He combustion reaction of hexane:

2 C6H14 + 19 O2 = 12 CO2 + 14 H2O

2 mol C6H14 ---------> 12 mol CO2
x mol C6H14 ---------> 18.4 mol CO2

12 * x = 18.4 * 2

12 x = 36.8

x = 36.8 / 12

x = 3.067 moles of CO2

hope this helps!.
5 0
3 years ago
Read 2 more answers
4. Who has the most sensitive taste buds?<br> adults<br> babies<br> teenagers<br> the elderly
jeka57 [31]

Answer:

Taste bufs

Explanation:

May be teenager or adult is the most probable answer because teenager and adult are fully developed species of human so they can have most sensitive taste bud

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT

5 0
2 years ago
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Scientific Notation - PLEASE HELP!
zmey [24]

Answer:

0.0931 is the ans i think

8 0
4 years ago
What is the mass of 2.9 moles of calcium? Explain please
Alik [6]

Answer:

116 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of calcium = 2.9 moles

Mass of calcium =.?

The mole and mass of a substance are related according to the following formula:

Mole = mass / molar mass

With the above formula, we can obtain the mass of calcium. This can be obtained as follow:

Number of mole of calcium = 2.9 moles

Molar mass of calcium = 40 g/mol

Mass of calcium =.?

Mole = mass / molar mass

2.9 = mass of calcium / 40

Cross multiply

Mass of calcium = 2.9 × 40

Mass of calcium = 116 g

Therefore, the mass of 2.9 moles of calcium is 116 g.

4 0
3 years ago
At a certain temperature the vapor pressure of pure chloroform (CHCl3) is measured to be 91. torr. Suppose a solution is prepare
OleMash [197]

Answer:

P_{CCl_4}=52.43torr

Explanation:

Hello there!

In this case, sine the solution of this problem require the application of the Raoult's law, assuming heptane is a nonvolatile solute, so we can write:

P_{CCl_4}=x_{CCl_4}P_{CCl_4}^{vap}

Thus, we first calculate the mole fraction of chloroform, by using the given masses and molar masses as shown below:

x_{CCl_4}=\frac{140/153.81}{140/153.81+67.1/100.21}=0.576

Therefore, the partial pressure of chloroform turns out to be:

P_{CCl_4}=0.576*91torr\\\\P_{CCl_4}=52.43torr

Regards!

3 0
3 years ago
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