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3 years ago

12

A hot cup of water has fewer molecules than a hot tub of water. This same cup of

2 answers:

Mrac [35]3 years ago

6 0

Answer:eeded to change the temperature of one gram of a substance one degree ... iron(specific heat=0.12 cal/g C) and a cup of water both have the same temperature. ... If you drop a hot rock into a pail of water,the temperature of the rock and the water ... Therefore, water molecules have higher specific heat capacity than metals

Explanation:

Mnenie [13.5K]3 years ago

5 0

Answer:

Answer:eeded to change the temperature of one gram of a substance one degree ... iron(specific heat=0.12 cal/g C) and a cup of water both have the same temperature. ... If you drop a hot rock into a pail of water,the temperature of the rock and the water ... Therefore, water molecules have higher specific heat capacity than metals

Explanation:

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Does the bowling ball have more potential energy or kinetic energy as it is halfway through its fall? Why?

ahrayia [7]

Answer:

more kinetic

Explanation:

I think the kinetic energy is 75 percent while the potential energy is 25 percent

5 0

4 years ago

What is the formula for carbon tetrachloride?<br> a. CCl<br> b. CCl2<br> c. CCl3<br> d. CCl4

Fittoniya [83]

The <span>formula for carbon tetrachloride is CCl4. The answer is letetr D. The rest of the choices do not answer the question above.</span>

7 0

3 years ago

Which of the following numerical expressions gives the number of particles in 2.0 g of Ne?

mojhsa [17]

Answer:

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

Explanation:

Step 1: Data give

Mass of Ne = 2.0 grams

Molar mass of neon = 20.18 g/mol

Number of Avogadro = 6.0 *10^23 /mol

Step 2: Calculate number of moles of neon

Moles Ne = Mass of ne / Molar mass of ne

Moles Ne = 2.0 / 20.18 g/mol

Moles Ne = 0.099 moles

Step 3: Calculate nulber of particles

Number of particles = 6.022*10^23 / mol * 0.099 moles = 5.96 *10^22

Number of particles = 6.022*10^23 * (2.0g/ 20.18g/mol)

Number of particles = 2.0 g*(6.0 x 10^23 particles/mol) / 20.18 g/mol

Option C is correct

7 0

3 years ago

tia_tia [17]

Vocabulary. Balanced chemical equation: A chemical equation in which the number of each type of atom is equal on the two sides of the equation.

Hope I helped! (´▽`)

__________________________________________________________

単語。平衡化学反応式：各タイプの原子の数が方程式の両側で等しい化学反応式。

私が助けてくれたらいいのに！(´▽`)

5 0

3 years ago

Read 2 more answers

If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?

myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30.17}\ year^{-1}$

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Initial concentration $[A_0]$ = ?

Final concentration $[A_t]$ = 12.5 grams

Applying in the above equation, we get that:-

$12.5\ g=[A_0]e^{-0.02297\times 90.6}$

$[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g$

<u>Mass of original sample = 100 g</u>

8 0

3 years ago