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Serggg [28]
3 years ago
8

An area of high air pressure is caused by _____.

Chemistry
1 answer:
DedPeter [7]3 years ago
7 0
Not totally sure, but I think it’s A.
You might be interested in
Describe any three activity and prepare report on process of sublimation and it uses im daily life​
Aleonysh [2.5K]

Answer:

Generally, a solid changes into liquid and then into gas state.

But the process of transistion of solid directly into gas without passing throuhg the intetmidiate stage, liquid is called sublimation.

Some of uses of sublimation are:

  1. Sublimation helps to dry substance within getting moist. This process of sublimation is also beneficial in medicine.
  2. Piriciple of sublimation is used in air freshener solids used in room and toilets. 
  3. Dry ice is the solid form CO2 gas whose sublimation is used as cooling agent and storing dead bodied.
  4. Camphor, a substance used in houseold sublimes to give a pleasant smell inside the house.

4 0
4 years ago
What is the number of electrons in an electrically neutral atom equivalent to?
dybincka [34]

Answer:

Option B = atomic number

Explanation:

Electrically neutral atom:

An electrically neutral atom have equal number of protons and neutrons. In other words we can say that negative and positive charges are equal in magnitude and cancel the each other. For example if neutral atom has 6 protons than it must have 6 electrons.  The number of protons or number of electrons are the atomic number of an atom while the number of protons and number of neutrons are the mass number of an atom. Every atom consist of nucleus or a positive center. The protons and neutrons are present with in the nucleus while electrons are present out side the nucleus. All these three subatomic particles construct an atom.

Example:

Consider the example of carbon. It consist of six protons and six electrons. So, its atomic number is six. While the six neutrons are also present in nucleus with six protons that’s why its mas number is 12.

Electron:

The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.

Symbol= e⁻

Mass= 9.10938356×10⁻³¹ Kg

It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.

Neutron and proton:

While neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.

Symbol of proton= P⁺  

Symbol of neutron= n⁰  

Mass of proton=1.672623×10⁻²⁷Kg

Mass of neutron=1.674929×10⁻²⁷ Kg

5 0
3 years ago
Read 2 more answers
PLEASE HELP!
Vadim26 [7]
I know all it's names,but i cann't say the value of yone in english.if u learn it to me i will help u.
8 0
3 years ago
Is this right ? I’m stuck on the Explanation part .
Alex777 [14]

Answer:

Lots of things here

Explanation:

Ammonia structure is written as NH3

carbon monoxide is CO

make bonds between O2, so there is 2 oxygen atoms per group,

anything with multiple elements bonded is a compound, thus your answer for carnon monoxide isnt correct, it should be CO for written and it is a compound. Fix your formula for ammonia and also max a bond between those two oxygens because it is O2 not O,

Your structure for SO2 is improper aswell, there are only 3 elements in this molecule, and usually the one out in front of the molecule is the central atom (except hydrogen). So it would go O-S-O for the structure, with only two bonding groups.

4 0
4 years ago
5) When heated in a flame, the element Indium emits electromagnetic radiation with a distinctive indigo blue
grandymaker [24]

Answer:

\lambda=451nm

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by using the following equation, defined in terms of energy, Planck's constant, wavelength and speed of light:

E=\frac{hC}{\lambda }

Thus, we solve for the wavelength as shown below:

\lambda=\frac{hC}{ E}

And finally plug in the energy, Planck's constant and speed of light to obtain:

\lambda=\frac{6.6261 x 10^{-34} m^2 kg / s*3x10^8m/s}{4.405x10^{-19}m^2kg/s^2}\\\\\lambda=4.513x10^{-7}m*\frac{1nm}{10^{-9}m} \\\\\lambda=451nm

Regards!

5 0
3 years ago
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