How much aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate? Answer in units of mol.

Chemistry

1 answer:

Bond [772]2 years ago

7 0

0.77 moles of aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate.

<h3>Equation of reaction</h3>

Al + Pb(NO₃)₂ ---> Al(NO₃)₃ + Pb (s)

From the equation of reaction:

1 mole of aluminum reacts with 1 mole of lead nitrate to produce 1 mole of aluminum nitrate

1 mole aluminum has a mass of 27 g

Number of moles of aluminum in 21 g = 21/27 =0.77 moles

0.77 moles of Aluminum produces 0.77 moles of aluminum nitrate

Therefore, 0.77 moles of aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate.

Learn more moles at: brainly.com/question/13314627

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