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12345 [234]
2 years ago
7

How much aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate? Answer in units of mol.

Chemistry
1 answer:
Bond [772]2 years ago
7 0

0.77 moles of aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate.

<h3>Equation of reaction</h3>
  • Al + Pb(NO₃)₂  ---> Al(NO₃)₃ + Pb (s)

From the equation of reaction:

1 mole of aluminum reacts with 1 mole of lead nitrate to produce 1 mole of aluminum nitrate

1 mole aluminum has a mass of 27 g

Number of moles of aluminum in 21 g = 21/27 =0.77 moles

0.77 moles of Aluminum produces 0.77 moles of aluminum nitrate

Therefore, 0.77 moles of aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate.

Learn more moles at: brainly.com/question/13314627

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A 7.5 L cylinder contains 5 moles of gas at a temperature of 274°C. What is its pressure in kiloPascals (kPa)?
AleksAgata [21]
<h3><u>Answer;</u></h3>

 = 3032.15 kPa

<h3><u>Explanation;</u></h3>

Using the equation;

PV = nRT , where P is the pressure,. V is the volume, n is the number of moles and T is the temperature and R is the gas constant, 0.08206 L. atm. mol−1.

Volume = 7.5 L, T = 274 +273 = 547 K, N = 5 moles

Therefore;

Pressure = nRT/V

               = (5 × 0.08206 × 547)/7.5 L

               = 29.925 atm

But; 1 atm = 101325 pascals

Hence; Pressure = 3032150.63 pascals

                            <u>= 3032.15 kPa</u>

               

3 0
3 years ago
Find the volume of 20g of benzene
sergey [27]

(d) Density of Benzene: 0.8786 g/cm cubed

(m) Mass: 20.00g

Formula to solve (v) volume of benzene: V=m/d

V=20g / 0.8786g/cm cubed

Answer: Volume of benzene is: 22.8 cm cubed  


Explanation: Well, density is mass divided volume. In this, it is what the volume is. All you need is mass divided by density. Hope this helps!

6 0
3 years ago
A sample of gas originally at 25 C and 1.00 atm pressure in a 2.5 L container is allowed to expand until the pressure is 0.85 at
aivan3 [116]

Answer:

Final volumeof the gas = 2.84 L

Explanation:

The formular to be used here is the general gas equation. the formular is being used because it gives the relationship between the three gas parameters (volume, temperature and pressure) mentioned.

The general gas equation is given as;

\frac{P1V1}{T1} = \frac{P2V2}{T2}

where;

P1 = initial pressure

V1 = initial volume

T1 = initial temperature

P2 = Final pressure

V2 = Final volume

T2 = Final temperature

From the question,

P1 = 1.00 atm

P2 = 0.85atm

T1 = 25C + 273 = 298K (Converting to kelvin)

T2 = 15C + 273 = 288K (Converting to kelvin)

V1 = 2.5L

V2 = ?

from the equation, making V2 subject of formula we have;

V2 = \frac{T2P1V1}{T1P2}

V2 = (1*2.5*288)/(298*0.85) = 2.84 L.

5 0
4 years ago
Problem: What is the kinetic energy of a 0.500 kg rabbit, running at 8.00 m/s? Calculate using the formula,
arsen [322]

Answer:

the answer s 9.000ms

Explanation:

that's the answer

4 0
3 years ago
According to the collision theory, what two factors must be true for a given collision to successfully create products?
Rainbow [258]

Answer:

Sufficient concentration and correct orientation of particles

Explanation:

The collision theory postulates that, for a chemical reaction to occur, there must be collision between reacting particles.

It implies that the rate of reaction depends on the number of collisions per unit time as well as the fraction that are successful or effective.

For collisions to be effective, there must be proper orientation of the particles and right concentration of the reactants.

  • The number of effective collisions and rate of reaction are directly proportional to the concentration of of the reactants.
8 1
3 years ago
Read 2 more answers
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