Given :
2.5 mole of Sulfuric acid .
To Find :
Mass of sodium hydroxide will completely neutralize 2.5 mol of sulfuric acid
Solution :
Let us assume volume of water be 1 L .
Now , we know , to neutralize 1 mole of sulfuric acid we need 2 moles of NaOH .
So , for 2.5 mole sulfuric acid required 5 mole of NaOH .
Moles of NaOH ,
Molecular mass of NaOH , M.M = 58.44 g/mol .
Mass of 5 moles of NaOH :
Hence , this is the required solution .
Answer:
CH4 + 2 O2 → CO2 + 2 H2O
Explanation:
There are one mole of O2 on the left side and on the right side there are three moles of O2. And to fix it you would need to make it two moles of O2 to have four molecules of O2 on the left side. Then you would make two moles of H2O to have a total of four moles of O2 on the right. Therefore, CH4 + 2 O2 → CO2 + 2 H2O is the answer.
Answer:
6. In order from left to right the balanced coeficcients are,
6, 1, 2, 3
8.
9. In order from left to right the balanced coeficcients are,
1, 11, 7, 8
Answer:125.0964g
Explanation:
Density = mass/volume
Density = 2.7 gcm-3
Volume=2.7*1.2*14.3=46.332
Mass=?
Mass= density* volume
= 2.7× 46.332=125.0964g