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12345 [234]
2 years ago
7

How much aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate? Answer in units of mol.

Chemistry
1 answer:
Bond [772]2 years ago
7 0

0.77 moles of aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate.

<h3>Equation of reaction</h3>
  • Al + Pb(NO₃)₂  ---> Al(NO₃)₃ + Pb (s)

From the equation of reaction:

1 mole of aluminum reacts with 1 mole of lead nitrate to produce 1 mole of aluminum nitrate

1 mole aluminum has a mass of 27 g

Number of moles of aluminum in 21 g = 21/27 =0.77 moles

0.77 moles of Aluminum produces 0.77 moles of aluminum nitrate

Therefore, 0.77 moles of aluminum nitrate can be found when 21g of aluminum react with lead (II) nitrate.

Learn more moles at: brainly.com/question/13314627

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A certain reaction with an activation energy of 185 kJ/mol was run at 505 K and again at 525 K . What is the ratio of f at the h
frosja888 [35]

Answer:

The ratio of f at the higher temperature to f at the lower temperature is 5.356

Explanation:

Given;

activation energy, Ea = 185 kJ/mol = 185,000 J/mol

final temperature, T₂ = 525 K

initial temperature, T₁ = 505 k

Apply Arrhenius equation;

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]

Where;

\frac{f_2}{f_1}  is the ratio of f at the higher temperature to f at the lower temperature

R is gas constant = 8.314 J/mole.K

Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1}  = 10^{0.7289}\\\\\frac{f_2}{f_1}  = 5.356

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356

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3 years ago
What do the coefficients in the following balanced chemical equation mean?
mafiozo [28]
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3 years ago
With all his gear, Neil Armstrong weighed 360 pounds on Earth. When he landed on the Moon, he weighed 60 pounds. Why?
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C. The gravity on the Moon is less than the gravity on Earth.

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The weight of Neil Armstrong changed because the gravity on the Moon is less than the gravity on earth. We can infer that the gravity on moon is one-sixth the gravity earth.

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