Answer: they all relate to eachother
Explanation: every star every planet every sun its hard to belive they relate
to eachother but only becuase there in the same UNIVERSE
When HCl reacts with a metal, hydrogen gas will be evolved. To test this gas, insert a burning splinter into the outlet of gas, the flame will be extinguished with a pop sound. This will confirm the gas is hydrogen.
Answer:
(slow)xy2+z→xy2z (fast) c step1:step2:xy2+z2→xy2z2
Explanation:
Step1: xy2+z2→xy2z2 (slow)
Step2: xy2z2→xy2z+z (fast)
2XY 2 + Z 2 → 2XY 2 Z
Rate= k[xy2][z2]
When the two elementary steps are summed up, the result is equivalent to the stoichiometric equation. Hence, this mechanism is acceptable. The order of both elementary steps is 2, which is ‘≤3’; this also makes this mechanism acceptable. Furthermore, the rate equation aligns with the experimentally determined rate equation, and this also makes this mechanism acceptable. Therefore, since all the three rules have been observed, this mechanism is possible.
Answer:
Option e and f are possible
Explanation:
Since we know that 0.264 gallon = 1L ⇒ we change this in all equations.
8.08 L * A =
a) 8.08 L * 0.264 gal / 8.08 L = 0.264 gal = 1L
b) 8.08 L * 8.08 gallon / 0.264L = (8,08/ 0.264) L/0.264 L = 30.61 / 0.264 = 115.93 L *8.08 L
c) 8.08 L * 8.08 gallon / 1L = (8,08/ 0.264) L/1 L = 30.61 L * 8.08 L
d) 8.08 L * 0.264 L / 1 gallon =8.08 L * 0.264 L / 1 gal
e) 8.08 L * 0.264 gallon / 1L = 8.08 L *1L / 1L = 8.08 L
f) 8.08 L * 1L / 0.264 gallon = 8.08L * 1L / 1L = 8.08 L
The last 2 options are possible ( e and f )
Answer:
120.0 mL.
Explanation:
- As it is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
We suppose that the initial W% of methanol is 100.0 %
<em>∴ (W%V) before dilution = (W%V) after dilution.</em>
W% before dilution = 100.0 %, V before dilution = 18.0 mL.
W% after dilution = 15.0 %, V after dilution = ??? mL.
<em>∴ V after dilution = (W%V) before dilution/W% after dilution = </em>(100.0 %)(18.0 mL)/(15.0%)<em> = 120.0 mL.</em>
