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3 years ago

9

What is the difference between thrust and applied force?

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

Thrust acts on the accelerated object in the direction opposite to the applied force hence it accelerates the object in the direction opposite to the applied force. ... Its magnitude is equal to that of applied force. It always increases the velocity of the object.

Explanation:

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The Moon has a radius of 1.7 × 106 m and a mass of 7.3 × 1022 kg. Find the gravitational field on the surface of the Moon.

Lisa [10]

Answer:

10.7* $10^{6}$

Explanation:

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3 years ago

Two identical ambulances with loud sirens are driving directly towards you at a speed of 40 mph. One ambulance is 2 blocks away

Rasek [7]

Answer:

c) The pitch of the two sirens sounds the same to you

Explanation:

The pitch does not depend on the distance of the object from the observer.

As per the given data

pitch = frequency

Frequency = $f_{0}$ $\frac{V +- V_{0}}{V +- V_{s}}$

$f^{'}$ = $f_{0}$ $\frac{V }{V - V_{s}}$

Hence, the pitch of the two sirens remains the same for the observer.

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3 years ago

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3 years ago

A car rolls backward from -2 to -10 m/s in 4 seconds. what is the acceleration. PLEASE HELP WILL GIVE BRAINLIEST

pashok25 [27]

$\bf \underline{Given : }$

Initial velocity,u = -2 m/s

Final velocity,v = -10 m/s

Time taken, t = 4 seconds

$\bf \underline{To \: find \: out : }$

Find the acceleration ( a ) .

$\bf \underline{Solution : }$

We know that,

$\sf \: Acceleration = \dfrac{v - u}{t}$

Substituting the values in the above formula, we get

$\implies \sf \: Acceleration = \dfrac{ - 10 - ( - 2)}{4}$

$\implies\sf \: Acceleration = \dfrac{ - 10 + 2}{4}$

$\implies \sf \: Acceleration = \cancel \dfrac{ - 8}{4}$

$\implies\sf \: Acceleration = - 2 \: ms {}^{ - 2}$

Hence,the acceleration of a body is -2 m/s².

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4 years ago

I attach a voltage source to a 45 mF capacitor until it is fully charged. I then take the voltage source away and discharge the

galben [10]

Answer:

60 V

Explanation:

Let the potential on capacitor be V . This will be equal to voltage of the source .

During discharge this voltage of capacitor will create current .

V / 120 = .5

V = 60 V

So this would have been the voltage of the source . So voltage of source

= 60 V

8 0

3 years ago

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