Answer:
115, 80, 15m
Explanation
t1 = 14s
t2 = 18s
change in time = 4s (18-14)
r(final) = r(initial) + (average velocity) x (change in time)
multiply the average velocity with the change in time
= (4, 0, -3) x 4 = 16, 0, -12
now we'll add this value to the initial position of the car
(99, 80, 27)m + (16, 0, -12)m = (115, 80, 15)m
1. 0.16 N
The weight of a man on the surface of asteroid is equal to the gravitational force exerted on the man:

where
G is the gravitational constant
is the mass of the asteroid
m = 100 kg is the mass of the man
r = 2.0 km = 2000 m is the distance of the man from the centre of the asteroid
Substituting, we find

2. 1.7 m/s
In order to stay in orbit just above the surface of the asteroid (so, at a distance r=2000 m from its centre), the gravitational force must be equal to the centripetal force

where v is the minimum speed required to stay in orbit.
Re-arranging the equation and solving for v, we find:

19,999,985 nomas creo y soy positivo que si es pero puedes ablar ingles
Answer:
n= 16021.03 slaps
Explanation:
Using law of Energy conservation
E_{thermal}= Kinetic energy of hand
⇒
m_h= mass of the hand = 0.4 kg
v_h= velocity of the hand = 10 m/s
n= number of slaps
c= 4180 J/Kg °C
m= mass of chicken = 1 kg
Assuming all the energy of hand goes into chicken
Given Ti=0°C and T_f= 170 F= 76.66°C
Now putting the values in above equation to get n

n= 16021.03 slaps
Velocity = 14 m/s
Time = 20 s
Displacement = Velocity×Time = (14×20) m = 280 m
The displacement is 280 m towards the direction of motion.