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bixtya [17]
3 years ago
11

A deep-space vehicle moves away from the Earth with a speed of 0.870c. An astronaut on the vehicle measures a time interval of 3

.10 s to rotate her body through 1.00 rev as she floats in the vehicle. What time interval is required for this rotation according to an observer on the Earth
Physics
1 answer:
kondaur [170]3 years ago
8 0

Answer:

t₀ = 1.55 s

Explanation:

According to Einstein's Theory of Relativity, when an object moves with a speed comparable to speed of light, the time interval measured for the event, by an observer in  motion relative to the event is not the same as measured by an observer at rest.

It is given as:

t = t₀/[√(1 - v²/c²)]

where,

t = time measured by astronaut in motion = 3.1 s

t₀ = time required according to observer on earth = ?

v = relative velocity = 0.87 c

c = speed of light

3.1 s = t₀/[√(1 - 0.87²c²/c²)]

(3.1 s)(0.5) = t₀

<u>t₀ = 1.55 s</u>

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mrs_skeptik [129]

Rock layers are folded and appear to be scratched because of the plate tectonics and the glacial advance.

Answer: Option 1 and 2.

<u>Explanation:</u>

Plate tectonics and the glacial advance are the geological phenomenon which have the power to effect the layers of the rock. Because of these, there can be scratches on the layers of the rock and the layers of the rocks can be folded.

The huge mass of ice that is included in the glacier which may be of thickness of three to four kilometers is a lot to scratch the rocks. These glaciers are responsible for moving the rocks from their original position to a new place altogether.

7 0
3 years ago
1. Is this circuit SERIES or PARALLEL?
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Answer:

Series

Explanation:

Because I listen to my science teacher

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2 years ago
The loss of static electricity as electric charges transfer from one object to another is called
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Answer: Static discharge
7 0
2 years ago
A superhero swings a magic hammer over her head in a horizontal plane. The end of the hammer moves around a circular path of rad
Korolek [52]

Answer:

9.21954 m/s

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Angle is zero

Explanation:

r = Radius of arm = 1.5 m

\omega = Angular velocity = 6 rad/s

The horizontal component of speed is given by

v_h=\omega r\\\Rightarrow v_h=6\times 1.5\\\Rightarrow v_h=9\ m/s

The vertical component of speed is given by

v_v=2\ m/s

The resultant of the two components will give us the velocity of hammer with respect to the ground

v=\sqrt{v_h^2+v_v^2}\\\Rightarrow v=\sqrt{9^2+2^2}\\\Rightarrow v=9.21954\ m/s

The velocity of hammer relative to the ground is 9.21954 m/s

Acceleration in the vertical component is zero

Net acceleration is given by

a_n=a_h=\omega^2r\\\Rightarrow a_n=6^2\times 1.5\\\Rightarrow a_n=54\ m/s^2

Net acceleration is 54 m/s²

As the acceleration is towards the center the angle is zero.

3 0
3 years ago
block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s). What is the angular frequen
faltersainse [42]

Answer:

Angular frequency is 20 rad/s.      

Explanation:

Given that,

A block is attached to an oscillating spring. The function below shows its position (cm) vs. time (s) is given by :

x(t)=1.5\cos(20\ t).....(1)

The general equation of oscillating particle is given by :

x(t)=A\cos(\omega t).......(2)

Compare equation (1) and (2) we get :

\omega=20\ rad/s

So, the angular frequency of the oscillation is 20 rad/s.

7 0
3 years ago
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