A 50-newton box is placed on an inclined plane that makes a 30° angle with the horizontal. Calculate the component of gravitatio
nal force that acts down the inclined plane. A. 25 N B. 37 N C. 43 N D. 56 N
2 answers:
Weight of the box = 50 Newtons
In the diagram attached,
The gravitational force is broken into two components.
The component of the gravitational force that acts along the inclined plane is 50 SinФ.
Ф = 30°
Sin 30° = 0.5
Gravitational force down the inclined plane = 50 Sin 30°
= 50 × 0.5
Gravitational force down the inclined plane = 25 Newtons or 25 N
Hence, the option A is correct.
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The final velocity becomes 31.48 m/s
<u>Explanation:</u>
Given:
Initial velocity, u = 33 m/s
Height, h = 5m
Final velocity, v = ?
According to Newton's law:
v² - u² = 2gh
where,
g is the acceleration due to gravity and
g = 9.8 m/s²
On substituting the values we get:
Therefore, the final velocity becomes 31.48 m/s