A 50-newton box is placed on an inclined plane that makes a 30° angle with the horizontal. Calculate the component of gravitatio
nal force that acts down the inclined plane. A. 25 N B. 37 N C. 43 N D. 56 N
2 answers:
Weight of the box = 50 Newtons
In the diagram attached,
The gravitational force is broken into two components.
The component of the gravitational force that acts along the inclined plane is 50 SinФ.
Ф = 30°
Sin 30° = 0.5
Gravitational force down the inclined plane = 50 Sin 30°
= 50 × 0.5
Gravitational force down the inclined plane = 25 Newtons or 25 N
Hence, the option A is correct.
You might be interested in
Since the tower base is square with a side length of 125 m,
Therefore,
Square root of 31250 = 176.776953 (Diameter) , so this is the diameter of the cylinder to enclose it, and radius, r = 88.38834765 m and height, h = 324 m.
The volume of cylinder,
Thus, the mass of the air in the cylinder,
Hence, the mass of the air in the cylinder is this more than the mass of the tower.