A. it bends when light reaches an end of a barrier it will bend.
Answer:
It's an Angle of incidence that provides a 90° angle but is also refracted at the same time. it's used to find the water-air boundary (which is 48.6 degrees). in addition, its an angle of incidence value.
Answer:
The boats are 934.65 feet apart
Explanation:
Given:
The angles of depression to the two boats are 42 degrees and 29 degrees
Height of the observation deck i = 1,353 feet
To Find:
How far apart are the boats (y )= ?
Solution:
<em><u>Step 1 : Finding the value of x(Refer the figure attached)</u></em>
We can use the tangent ratio to find the x value


x = 590.47 feet
<em><u>Step 2 : Finding the value of z (Refer the figure attached)</u></em>


z = 1525.12 feet
<em><u>Step 3 : Finding the value of y (Refer the figure attached</u></em>)
y = z -x
y = 1525.12 - 590.47
y = 934.65 feet
Thus the two boats are 934.65 feet apart
The number of times a standard quantity is present in the given physical quantity is called magnitude of a physical quantity
Answer:
P = 2i + 5j
Therefore she is 2 blocks east and 5 blocks north.
Resultant P = √(2^2 + 5^2) = √(4+25) = √29 = 5.4 blocks
Angle = taninverse (5/2)
Angle = 68.2°
Explanation:
Given:
Let west be negative and east be positive x axis.
Let north be the positive y axis.
5.00blocks west = -5.00 i
5.00 blocks north = 5.00 j
7.00 blocks east = 7.00i
Addition of the vector form of hee position is;
P = -5i +7i -5j
P = 2i + 5j
Therefore she is 2 blocks east and 5 blocks north.
Resultant P = √(2^2 + 5^2) = √(4+25) = √29 = 5.4 blocks
Angle = taninverse (5/2)
Angle = 68.2°