A 50-newton box is placed on an inclined plane that makes a 30° angle with the horizontal. Calculate the component of gravitatio
nal force that acts down the inclined plane. A. 25 N B. 37 N C. 43 N D. 56 N
2 answers:
Weight of the box = 50 Newtons
In the diagram attached,
The gravitational force is broken into two components.
The component of the gravitational force that acts along the inclined plane is 50 SinФ.
Ф = 30°
Sin 30° = 0.5
Gravitational force down the inclined plane = 50 Sin 30°
= 50 × 0.5
Gravitational force down the inclined plane = 25 Newtons or 25 N
Hence, the option A is correct.
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Answer:
(a) 1 : 2
(b) same
Explanation:
Let the mass of puck A is m and the mass of puck B is 2 m.
initial speed for both the pucks is same as u and the distance is same for both is s.
let the tension is T for same.
The kinetic energy is given by
(a) As the speed is same, so the kinetic energy depends on the mass.
So, kinetic energy of A : Kinetic energy of B = m : 2m = 1 : 2
(b) A the distance s same so the final velocities are also same.
where:
F - force
m - mass
a - acceleration
We transform this formula to get a: