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ikadub [295]
3 years ago
11

A 50-newton box is placed on an inclined plane that makes a 30° angle with the horizontal. Calculate the component of gravitatio

nal force that acts down the inclined plane. A. 25 N B. 37 N C. 43 N D. 56 N

Physics
2 answers:
dedylja [7]3 years ago
3 0

Weight of the box = 50 Newtons

In the diagram attached,

The gravitational force is broken into two components.

The component of the gravitational force that acts along the inclined plane is 50 SinФ.

Ф = 30°

Sin 30° = 0.5

Gravitational force down the inclined plane = 50 Sin 30°

= 50 × 0.5

Gravitational force down the inclined plane = 25 Newtons or 25 N

Hence, the option A is correct.

Orlov [11]3 years ago
3 0

The correct answer is A) 25 N i took the test and got it correct

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Answer:

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a 4kg block is attatched to a vertical sspring constant 800n/m. the spring stretches 5cm down. how much elastic potential energy
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The Potential energy stored in the system is 1 J

<u>Explanation:</u>

Given-

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We know,

Change in potential energy is equal to the work done.

So,

U = \frac{1}{2} k (x)^2\\\\

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3 years ago
During the motion of the slinky in a transverse wave, what do the particles of the slinky coil do?
Mazyrski [523]

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C.) The slinky particles move up and down

Explanation:

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5 0
2 years ago
A strontium vapor laser beam is reflected from the surface of a CD onto a wall. The brightest spot is the reflected beam at an a
sladkih [1.3K]

Answer:

d=1.29*10^{-6}m

Explanation:

From the question we are told that:

Distance of wall from CD D=1.4

Second bright fringe y_2= 0.803 m

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2/25/20 or 2/28/20 Dispatch #53
mixer [17]

Answer:

Power = 21[W]

Explanation:

Initial data:

F = 35[N]

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In order to solve this problem we must remember the definition of work, which tells us that it is equal to the product of a force for a distance.

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