3 years ago

Bleach is a 0.750 M solution of sodium hypochlorite. What volume, in litres, would contain 120.3 g of sodium hypochlorite?

Chemistry

1 answer:

Lady bird [3.3K]3 years ago

4 0

Answer:

2.15 L

Explanation:

M(NaOCl) = 23.0 + 16.0 + 35.5 = 74.5 g/mol

120.3 g *1 mol/74.5 g = 1.615 mol NaOCl

0.750 M = 0.750 mol/L

1.615 mol * 1L/0.750 mol = 2.15 L

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C3H8 + 5O2 → 3CO2+ 4H2O, if 5.75L of oxygen are consumed in the above reaction, how many L of carbon dioxide are produced?

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Answer: 3.45 L carbon dioxide are produced

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{5.75L}{22.4L}=0.257moles$

$C_3H_8+5O_2(g)\rightarrow 3CO_2+4H_2O$

According to stoichiometry :

5 moles of $O_2$ produce = 3 moles of $CO_2$

Thus 0.257 moles of $O_2$ will produce= $\frac{3}{5}\times 0.257=0.154moles$ of $CO_2$

Volume of $CO_2=moles\times {\text {Molar volume}}=0.154moles\times 22.4L/mol=3.45$

Thus 3.45 L carbon dioxide are produced

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