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3 years ago

You have just performed a laboratory activity where a lot of chemical waste was produced. all of the chemical wastes should be

Chemistry

2 answers:

Katyanochek1 [597]3 years ago

7 0

D. Disposed of according to your teachers instructions

hoa [83]3 years ago

7 0

Answer:

The correct option is d

Explanation:

There are several ways of harmlessly disposing chemical wastes and as such some chemical wastes have special disposal methods (for example hazardous wastes such as inflammable wastes, corrosive wastes and poisonous wastes).

For the reasons above, it is necessary for the teacher's instruction to be followed in disposing the waste because the teacher will have a better knowledge of the class of waste and the best method to harmlessly dispose such waste (most especially because of the large waste produced) .

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Calculate the grams of C6H6 needed to produce 25 g of CO2<br> Show your work

Anna007 [38]

Answer:

The given reaction is a combustion reaction of benzene,

. From its balanced chemical equation,

→

the mass of carbon dioxide

(

)

produced from 20 grams (g) of

is determined through the molar mass of the two compounds, given by,

44.01

78.11

and their mole ratio:

→

With this,

(

)

(

78.11

)

(

)

(

44.01

)

(

)

(

)

(

44.01

)

78.11

5281.2

78.11

67.6

Therefore, the mass in grams of

formed from 20 grams of

67.6

it is a problem of app

3 0

2 years ago

A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de

jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

= 5.312 %

≅ 5.3%

3 0

3 years ago

Identify the types of information that are necessary to communicate with emergency responders. Select one or more: Any chemicals

oksano4ka [1.4K]

Answer:

How the incident happened

Any chemicals involved in an incident

Any other hazards present in the lab

Explanation:

Above are the types of information that are necessary to communicate with emergency responders. The emergency responders ask the first question that how the incident happened. After that they ask that is there any harmful chemicals are present in the laboratory or what types of chemicals present in the laboratory. These questions were asked by the emergency responders in order to give the patient a suitable treatment.

8 0

3 years ago

Question 2 of 50

wolverine [178]

The thermal decomposition of calcium carbonate will produce 14 g of calcium oxide. The stoichiometric ratio of calcium carbonate to calcium oxide is 1:1, therefore the number of moles of calcium carbonate decomposed is equal to the number of moles of calcium oxide formed.

Further Explanation:

To solve this problem, follow the steps below:

Write the balanced chemical equation for the given reaction.
Convert the mass of calcium carbonate into moles.
Determine the number of moles of calcium oxide formed by using the stoichiometric ratio for calcium oxide and calcium carbonate based on the coefficient of the chemical equation.
Convert the number of moles of calcium oxide into mass.

Solving the given problem using the steps above:

STEP 1: The balanced chemical equation for the given reaction is:

$CaCO_{3} \rightarrow \ CaO \ + \ CO_{2}$

STEP 2: Convert the mass of calcium carbonate into moles using the molar mass of calcium carbonate.

$mol \ CaCO_{3} \ = 25 \ g \ CaCO_{3} \ (\frac{1 \ mol \ CaCO_{3}}{100.0869 \ g \ CaCO_{3}})\\ \\\boxed {mol \ CaCO_{3} \ = 0.2498 \ mol}$

STEP 3: Use the stoichiometric ratio to determine the number of moles of CaO formed.

For every mole of calcium carbonate decomposed, one more of a calcium oxide is formed. Therefore,

$mol \ CaO \ = 0.2498 \ mol$

STEP 4: Convert the moles of CaO into mass of CaO using its molar mass.

$mass \ CaO \ = 0.2498 \ mol \ CaO \ (\frac{56.0774 \ g \ CaO}{1 \ mol \ CaO})\\ \\mass \ CaO \ = 14.008 \ g$

Since there are only 2 significant figures in the given, the final answer must have the same number of significant figures.

Therefore,

$\boxed {mass \ CaO \ = 14 \ g}$

Learn More

Learn more about stoichiometry brainly.com/question/12979299
Learn more about mole conversion brainly.com/question/12972204
Learn more about limiting reactants brainly.com/question/12979491

Keywords: thermal decomposition, stoichiometry

5 0

3 years ago

Which of the following units would be the most appropriate for measuring the thickness of a piece of paper? A. centimeters B. mi

Alla [95]

B, millimeters because paper is really thin therefore it'd require small measurements for units.

3 0

3 years ago