By using Lami's theorem formula, the tension in the supporting wires is 48.6 Newtons
TENSION
- Tension is also a force having Newton as S.I unit.
- The tension in the wire will be the same.
This question can be solved by using either vector diagram or by using Lami's theorem.
The sum of two given angles = 42 + 42 = 84 degrees
The third angle = 180 - 84 = 96 degrees.
Below is the Lami's theorem formula
Where
= 42 + 90 = 132 degrees
Y = 96 degrees
W = 65 N
By using the formula, we have
T/sin 132 = 65/sin96
Cross multiply
T = 0.743 x 65.57
T = 48.56 N
Therefore, the tension in the supporting wires is 48.6 Newtons approximately.
Learn more about Tension here: brainly.com/question/24994188
Answer:
1.) 11 km/s
2.) 9.03 × 10^-5 metres
Explanation:
Given that an electron enters a region of uniform electric field with an initial velocity of 64 km/s in the same direction as the electric field, which has magnitude E = 48 N/C.
Electron q = 1.6×10^-19 C
Electron mass = 9.11×10^-31 Kg
(a) What is the speed of the electron 1.3 ns after entering this region?
E = F/q
F = Eq
Ma = Eq
M × V/t = Eq
Substitute all the parameters into the formula
9.11×10^-31 × V/1.3×10^-9 = 48 × 1.6×10^-19
V = 7.68×10^-18 /7.0×10^-22
V = 10971.43 m/s
V = 11 Km/s approximately
(b) How far does the electron travel during the 1.3 ns interval?
The initial velocity U = 64 km/s
S = ut + 1/2at^2
S = 64000×1.3×10^-6 + 1/2 × 8.4×10^12 × ( 1.3×10^-9)^2
S =8.32×10^-5 + 7.13×10^-6
S = 9.03 × 10^-5 metres
Answer:
v = 3.27 m/s
Explanation:
KE = 1/2 mv^2
695 J = 1/2 (130kg)(v^2)
695 J / (1/2 x 130kg) = v^2
v^2 = square root of 10.69
v = 3.27 m/s
A solution is a value or a collection of values.. when substituted for the unknowns, the equation become an equality.
Example : x + 2 = 7
When we out the 5 in place of x we get: 5 + 2 = 2
