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Elodia [21]
3 years ago
15

Why it is difficult to run fast in sand​

Physics
2 answers:
balu736 [363]3 years ago
8 0
Running on sand requires 1.6 times more energy spent than running on hard surface, so the force applied by our foot on sand is less.
prohojiy [21]3 years ago
5 0

Explanation:

The force exerted by our foot on the sand is less because time taken is large so it is difficult to run fast on sand.

hope it will help you

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Weight and mass are interchangeable terms. True or False
Nonamiya [84]
It's false. Mass is a way of measuring how much matter an object contains, where as weight measures how hard gravity is pulling on an object. While on earth, these are typically interchangeable. However, if you were to go to Mars, your mass would stay the same, but the weight will be different. This is because you still contain the same amount of matter, but the gravity's pull will be different because the moon has a different gravitational pull than the earth. Hope this helps!
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3 years ago
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Two samples of aluminum foil, 27 grams and 54 grams, are cut out from a roll. Which of the following properties is different for
Delicious77 [7]
Before answering this question, you must know the concept between extensive and intensive property. The extensive property does not depend on the amount of substance (like mass), which is the opposite of intensive properties. From the given choices, the rest are extensive properties except for <em>amount of matter</em>. Hence, that is the answer.
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4 years ago
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A spherical mirror gives an image magnified 5 times at a distance 5 m. determine whether the mirror is convex or concave? How mu
irakobra [83]

Answer:

1. Concave mirror.

2. 4.17 m or 417 cm.

Explanation:

The following data were obtained from the question:

Object distance (u) = 5 m

Magnification (M) = 5

Focal length (f) =..?

1. Identification of the mirror.

To determine whether or not the mirror is concave or convex, we must first of all calculate the image distance.

This can be obtained as follow:

Object distance (u) = 5 m

Magnification (M) = 5

Image distance (v) =.?

Magnification (M) = image distance (v) /object distance (u).

M = v/u

5 = v/5

Cross multiply

v = 5 x 5

v = 25 m

Since the image distance obtained is positive, the mirror is said to be a concave mirror.

2. Determination of the focal length of the mirro.

This can be obtained as follow:

Object distance (u) = 5 m

Image distance (v) = 25 m

Focal length (f) =...?

1/f = 1/v + 1/u

1/f = 1/25 + 1/5

1/f = 0.04 + 0.2

1/f = 0.24

Cross multiply

f x 0.24 = 1

Divide both side by 0.24

f = 1/0.24

f = 4.17 m

Converting the focal length of cm, we have:

1 m = 100 cm

Therefore, 4.17 m = 4.17 x 100 = 417 cm

Therefore, the focal length of the mirror is 4.17 or 417 cm.

4 0
3 years ago
I NEED SOMEONES HELP which statements are true regarding scientific evidence supporting the big bang theory
Elena-2011 [213]
The answer is A,B,C that apply. I believe this is the answer i hope this helps have a good day.
7 0
3 years ago
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Which one of the following statements concerning emf is true?
Andrej [43]

Answer:

C) Emf is the force exerted on a single charge to move it from one terminal to the other of an emf device.

Explanation:

Electromotive force, abbreviation E or emf, electrical energy per unit supplied from an energy source, such as an electrical generator or a battery. In the engine or battery, electricity is transformed from one source to another as the device works on the electrical charge that is passed within itself.

In physics it is defined as Work done by a cell or battery in moving a unit charge from its one terminal to the other, against the potential.

Hence C is correct

3 0
3 years ago
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