What is the mass in pounds of 1.000 quart of mercury

14 km is how many centimeters?

Yuki888 [10]

Answer:

1400000 cm

Explanation:

14 km equals to 1400000 cm (14 km = 1400000 cm)

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8 0

3 years ago

A solution that is a 4 on pH scale is a

Dominik [7]

A pH scale runs from 1 to 14 with 7 being neutral.

1-6 has base like properties
8-14 has avid line properties

since this solution has a pH scale of 4.... the solution is basic

3 0

3 years ago

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6CO2 + 6 H2O —> C6H12O6 + 6O2

PilotLPTM [1.2K]

Answer:

The answer to your question is 0.5 moles

Explanation:

Data

moles of Glucose = ?

moles of carbon dioxide = 3

Balanced chemical reaction

6CO₂ + 6H₂O ⇒ C₆H₁₂O₆ + 6O₂

Process

To solve this problem, use proportions, and cross multiplication.

Use the coefficients of the balanced equation.

6 moles of CO₂ ----------------- 1 mol of C₆H₁₂O₆

3 moles of CO₂ ---------------- x

x = (3 x 1) / 6

-Simplification

x = 3/6

-Result

x = 0.5 moles of Glucose

3 0

3 years ago

Which describes a possible path a carbon atom could take through the carbon cycle?

Elodia [21]

Answer:

I know for a fact the correct answer is B

8 0

3 years ago

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Air at 7S°F and14.6 though a cfm(cubic ft per minute) and the The flow rate is 48000 psia flows though a rectangular duct of Ix2

IgorLugansk [536]

Explanation:

The given data is as follows.

Air is at $75^{o}F$ and 14.6 psia.

$\varepsilon$ = 0.00015 ft, Flow rate, (Q) = 48000 $ft^{3}/m$

(a) Formula to calculate hydraulic radius $(r_{H})$ is as follows.

$r_{H} = \frac{\text{free flow area}}{\text{wet perimeter}}$

= $\frac{2 \times 1}{2(1) + 2(2)}$

= $\frac{1}{3}$ ft

Formula for equivalent diameter is as follows.

$D_{eq} = 4 \times r_{H}$

= $4 \times \frac{1}{3} ft$

= $\frac{4}{3}$ ft

(b) Formula for velocity floe is as follows.

Q = VA

V = $\frac{Q}{A}$

= $\frac{48000}{2 \times 1}$ ft/min

= 24000 ft/min

(c) Formula to calculate Reynold's number is as follows.

$R_{e}$ = $\frac{D \times V \times \rho}{\mu}$

= $\frac{\frac{4}{3} \times 24000 \times 0.0744}{0.0443}$ (as $\rho = 0.0744 lb/ft^{3}$ and $\mu$ = 0.0443 lb/ft. hr)

= 53742.66 hr/min

As 1 hr = 10 min. So, $53742.66 hr/min \times \frac{60 min}{1 hr}$

= 3224559.6

(d) Formula to calculate pressure drop $(\Delta P)$ is as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

Putting the given values into the above formula as follows.

$\frac{\Delta P}{L} = \frac{4f \rho V^{2}}{2Dg_{c}}$

= $\frac{4 \times 0.00015 \times 100 \times 0.0744 \times (24000)^{2}}{2 \times \frac{4}{3} \times {4}{3}}$

= 6.238 $lb/ft^{2}$

5 0

3 years ago