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Lyrx [107]
2 years ago
11

Vectors vs Scalar

Physics
1 answer:
IrinaK [193]2 years ago
7 0

Answer:

I wish I knew

Explanation:

Ummm

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A 97.0 kg ice hockey player hits a 0.150 kg puck, giving the puck a velocity of 48.0 m/s. If both are initially at rest and if t
OverLord2011 [107]

Answer:

s₁ = 0.022 m

Explanation:

From the law of conservation of momentum:

m_1u_1 + m_2u_2 = m_1v_1+m_2v_2

where,

m₁ = mass of hockey player = 97 kg

m₂ = mass of puck = 0.15 kg

u₁ = u₂ = initial velocities of puck and player = 0 m/s

v₁ = velocity of player after collision = ?

v₂ = velocity of puck after hitting = 48 m/s

Therefore,

(97\ kg)(0\ m/s)+(0.15\ kg)(0\ m/s)=(97\ kg)(v_1)+(0.15\ kg)(48\ m/s)\\\\v_1 = -\frac{(0.15\ kg)(48\ m/s)}{97\ kg} \\v_1 = - 0.074 m/s

negative sign here shows the opposite direction.

Now, we calculate the time taken by puck to move 14.5 m:

s_2 =v_2t\\\\t = \frac{s_2}{v_2} = \frac{14.5\ m}{48\ m/s} \\\\t =  0.3\ s

Now, the distance covered by the player in this time will be:

s_1 = v_1t\\s_1 = (0.074\ m/s)(0.3\ s)

<u>s₁ = 0.022 m</u>

4 0
2 years ago
Si: A + B = C – D es una ecuación física donde A, B, C y D son magnitudes físicas entonces [ A ] = [ B ] = [ C ] = [ D ]
PilotLPTM [1.2K]

Answer:

[A] = [B] = [C] = [D] por el Principio de Homogeneidad Dimensional y el uso de operaciones de adición y sustracción.

Explanation:

Por el Principio de Homogeneidad Dimensional, A, B, C y D deben tener las mismas magnitudes físicas para la realización de operaciones de adición y sustracción. Es decir:

[A] + [B] = [C] - [D], donde [A] = [B] = [C] = [D]

8 0
2 years ago
Suppose a point charge is located at the center of a spherical surface. The electric field at the surface of the sphere and the
emmasim [6.3K]

Answer:

<em>The flux through the sphere will remain the same, and the magnitude of the electric field will increase by four times.</em>

Explanation:

The electric flux is the number of electric field, passing through a given area. It is proportional to the electric field strength and the area through which this field passes.

If the radius of the sphere is halved, the area of the sphere will reduce by square of the reduction, which will be four times. The electric field lines will become closer together, or technically increase by a fourth of its initial value. The resultant effect is that the electric flux will remain the same.

If originally,

Φ = EA cos∅

where Φ is the electric flux through the sphere

E is the electric field on the sphere

A is the area of the sphere.

If the area of the sphere is reduced to half, then,

the area reduces to A/4,

and the electric field increases to be 4E on the sphere.

The flux now becomes

Φ = 4E x A/4 cos∅

which reduces to

Φ = EA cos∅

which is the initial electric flux on the sphere.

8 0
2 years ago
Suppose you are observing the interference pattern formed by a Michelson interferometer in a laboratory and a joking colleague h
Troyanec [42]

Answer:

Explanation:

In Michelson interferometer , two light waves from different directions are made to overlap so that fringes are formed on the screen due to interference . In it,  two monochromatic and coherent light are made to overlap which have some path difference or phase difference. They form dark and bright fringes .

Now when a match stick is lit in the path of a wave , the fringes will disappear  and an general illumination will be observed on the screen as the light from the lit match stick will not be coherent . Incoherent light can not form stable fringes.

7 0
3 years ago
A 61 kg skater is traveling at 2.5 m/s while carrying a 4.0 kg bowling ball. After he throws the bowling ball forward at twice t
gregori [183]

The final velocity of the skater is 2.34 m/s forward

Explanation:

We can solve this problem by using the law of conservation of momentum. In fact, the total momentum of the system before and after the ball is thrown must be conserved, in absence of external forces.

Before the ball is thrown, the total momentum is:

p_i = (M+m)u

where

M = 61 kg is the mass of the skater

m = 4.0 kg is the mass of the ball

u = 2.5 m/s (forward) is the combined velocity of the skater and the ball

After, the ball is thrown at twice the velocity, so the final total momentum is

p_f = MV+mv

where

V is the final velocity of the skater

v = 2(2.5) = 5.0 is the final velocity of the ball

Since the total momentum must be conserved, we can write

p_i = p_f\\(M+m)u = MV+mv\\V=\frac{(M+m)u-mv}{M}=\frac{(61+4.0)(2.5)-(4.0)(5.0)}{61}=2.34 m/s

So, the skater is moving at 2.34 m/s (forward) after the shot.

Learn more about momentum:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

brainly.com/question/9484203

#LearnwithBrainly

5 0
3 years ago
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