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Lyrx [107]
3 years ago
11

Vectors vs Scalar

Physics
1 answer:
IrinaK [193]3 years ago
7 0

Answer:

I wish I knew

Explanation:

Ummm

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Which of the following are vector quantities? Check all that apply.
Dennis_Churaev [7]
It’s distance for my answer but tell me if anyone tells u this answer thanks
8 0
3 years ago
You pick up a 10-newton book off the floor and put it on a shelf 2 meters high. How much work did you do?​
Murljashka [212]

Answer:

20 J

Explanation:

Given:

Weight of the book is, W=10\ N

Height or displacement of the book is, d=2\ m

The work done on the book to raise it to a height of 2 m on a shelf is against gravity. The gravitational force acting on the book is equal to its weight. Now, in order to raise it, an equal amount of force must be applied in the opposite direction.

So, the force applied by me should be equal to weight of the body and in the upward direction. The displacement is also in the upward direction.

Now, work done by the applied force is equal to the product of force applied and displacement of book in the direction of the applied force.

Therefore, work done is given as:

Work=W\times d\\Work=10\times 2=20\ J

Therefore, the work done to raise a book to a height 2 m from the floor is 20 J.

3 0
3 years ago
Read 2 more answers
Forest protect the soil from erosion ? True or False
Ivenika [448]

Answer:

<h2><em>True</em></h2>

Forests helps in binding the soil together. Thus, prevent soil from erosion.

4 0
2 years ago
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Where should clouds form and why
LiRa [457]

Answer:

When air rises in the atmosphere it gets cooler and is under less pressure. When air cools, it's not able to hold all of the water vapor it once was. Air also can't hold as much water when air pressure drops. The vapor becomes small water droplets or ice crystals and a cloud is formed.

Explanation:

hope this helps.

8 0
3 years ago
Use Hooke's Law to determine the work done by the variable force in the spring problem. Nine joules of work is required to stret
natima [27]

Answer:

29.16 J

Explanation:

From Hook's law,

W = 1/2(ke²)..................... Equation 1

Where W = work done, k = Spring constant, e = extension.

Given: W = 9 J, e = 0.5 m.

Substitute into equation 1

9 = 1/2(k×0.5²)

Solve for k

k = 18/0.5²

k = 72 N/m.

The work done required to stretch the spring by additional 0.4 m is

W = 1/2(72)(0.4+0.5)²

W = 36(0.9²)

W = 29.16 J.

6 0
3 years ago
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