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3 years ago

An ___________ is a current-carrying wire wrapped around an iron core.

Physics

2 answers:

mestny [16]3 years ago

4 0

That could be an electromagnet,
and it could also be an solenoid.

Rasek [7]3 years ago

4 0

Your answer is simply, a <span>electromagnet.</span>

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In introductory physics laboratories, a typical Cavendish balance for measuring the gravitational constant G uses lead spheres o

SVETLANKA909090 [29]

Answer:

$F = 7.7*10^{-10}N$

Explanation:

You need to be careful with units for this problem. The force will be:

$F =\frac{K*m1*m2}{d^2}$

$F=\frac{6.67259 * 10^{-11}*1.56*21.1*10^{-3}}{(5.34*10^{-2})^2}$

$F=7.7*10^{-10}N$

8 0

3 years ago

Suppose you wish to whirl a pail full of water in a vertical circle at a constant speed without spilling any of its contents (ev

Yanka [14]

Answer:

V = 2.87 m/s

Explanation:

The minimum speed required would be that at which the acceleration due to gravity is negated by the centrifugal force on the water.

Thus, we simply need to set the centripetal acceleration equal to gravity and solve for the speed V using the following equation:

Centripetal acceleration = V^2 / r

where r is the distance of water from the pivot or shoulder.

For our case, r will be 0.65 + 0.19 = 0.84 m

and solving the above equation we get:

9.81 = V^2 / 0.84

V^2 = 8.2404

V = 2.87 m/s

6 0

3 years ago

How long will it take to travel 546 km at 110 km/hr (answer in hours)

Andre45 [30]

(60 * 546) / 110 = 297

297 hrs.

3 0

3 years ago

A tube of mercury with resistivity 9.84 × 10 -7 Ω ∙ m has an electric field inside the column of mercury of magnitude 23 N/C tha

slava [35]

Answer:

The current through the tube is 73.39A.

Explanation:

The relationship between the resistivity $\rho$ , the electric field $E$ , and the current density $J$ is given by

$\rho = \dfrac{E}{J}$

This equation can be solved for $J$ to get:

$J = \dfrac{E}{\rho}$

Since the current is $I = J\cdot A$

$I= J\cdot A = \dfrac{E}{\rho} \cdot A$

Now, for the tube of mercury $\rho = 9.84*10^{-7}\: \Omega \cdot m$ , $E = 23N/C$ , and the area is $A = \pi r^2 = \pi (1.0*10^{-3}m)^2 = 3.14*10^{-6}m^2$ ; therefore,

$I= \dfrac{23N/C}{9.84*10^{-7}\Omega\cdot m } *3.14*10^{-6}m^2$

$\boxed{I = 73.39A.}$

Hence, the current through the mercury tube is 73.39A.

5 0

4 years ago

Compare and contrast the velocity and speed equation

Alecsey [184]

Answer:

Explanation: The short answer is that velocity is the speed with a direction, while speed does not have a direction. Speed is a scalar quantity—it is the magnitude of the velocity. Speed is measured in units of distance divided by time

4 0

4 years ago