When light moves from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle above which there is no refracted ray, and it is given by:

(2)
where

is the refractive index of the second medium and

is the refractive index of the first medium.
We can find the ratio

by using Snell's law:

(1)
where

is the angle of incidence

is the angle of refraction
By using the data of the problem and re-arranging (1), we find

and if we use eq.(2) we can now find the value of the critical angle:
Answer:
10
Explanation:
(r) = <10 cos 6t, 10 Sin 6t>
The distance traveled by the object is the magnitude of vector r.
The magnitude of vector r is given by


r = 10
Answer:
1. Primary or P waves are push and pull waves
2. Secondary, S or Shear Waves are also called transverse wave
3. L or surface waves reach the earth's surface after P and S waves
Answer:
C) 26.6
Explanation:
I don't know how to calculate vector
Answer:
incomplete question, resistor must be there
Explanation: