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3 years ago

Find the angle 25 points for you plus a brainliest, thanks and 5 star

Mathematics

2 answers:

Hatshy [7]3 years ago

8 0

Answer:

The angle is approximately 23°

Step-by-step explanation:

let the angle be ∆

using trigonometrical identity,

tan ∆=3/7

tan∆=0.4286

∆=tan^-1(0.4286)

∆=23.19°

kondaur [170]3 years ago

7 0

Answer:

? =64.62306

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos theta = adjacent side / hypotenuse

cos ? = 3/7

Taking the inverse cos of each side

cos ^-1 ( cos ? ) = cos ^-1 (3/7)

? =64.62306

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Step-by-step explanation:

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The constant rate of change is 82

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3 years ago

How many 2/15 meter pieces of wood can you cut from a piece that is 2/3 meter long?

Dmitry_Shevchenko [17]

You are cutting wood into equally sized pieces so if you know the length of the wood and the size of the cuts...

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4 years ago

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the length of a rectangle is 7 inches more than its width, if the perimiter of the rectangle is 66 inches, find its dimensions.

Maurinko [17]

Perimeter of rectangle=66
length of rectangle=L
width of rectangle=w
P of a rect.= 2(length)+ 2(width)
66= 2L+2w

if the length is 7in more than the width, then
L=7+w

Now we will substitute 7+w in for L. Here is our new equation:

66=2(7+w) + 2w

Solve for w

66=14+2w+2w
66=14+4w
52=4w
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4 years ago

Graph the functions on the same coordinate axis. {f(x)=−2x+1g(x)=x2−2x−3

NikAS [45]

Answer:

(2,-3) and (-2,5)

Step-by-step explanation:

Let us graph the two equations one by one.

1. $f(x)=-2x+1$

If we compare this equation with the slope intercept form of a line which is given as

$y=mx+c$

we see that m = -1 and c =1

Hence the slope of the line is -2 and the y intercept is 1. Hence one point through which it is passing is (0,1) .

Let us find another point by putting x = 1 and solving it for y

$y=-2(1)+1$

$y=-2+1 = -1$

Let us find another point by putting x = 2 and solving it for y

$y=-2(2)+1$

$y=-4+1 = -3$

Hence the another point will be (2,-3)

Let us find another point by putting x = -2 and solving it for y

$y=-2(-2)+1$

$y=+1 = 5$

Hence the another point will be (-2,5)

Now we have two points (0,1) ,(1,-1) , (2,-3) and (-2,5) we joint them on line to obtain our line

$g(x)=y=x^2-2x-3$

$y=x^2-2x+1-1-3$

$y=(x-1)^2-4$

$(y+4)=(x-1)^2$

It represents the parabola opening upward with vertices (1,-4)

Let us mark few coordinates so that we may graph the parabola.

i) x=0 ; $y=y=(0)^2-2(0)-3=0-0-3=-3$ ; (0,-3)

ii)x=-1 ; $y=(-1)^2-2(-1)-3=1+2-3=0$ ; (-1,0)

iii) x=2 ; $y=(2)^2-2(2)-3 = 4-4-3 =-3$ ;(2,-3)

iii) x=1 ; $y=(1)^2-2(1)-3 = 1-2-3 =-4$ ;(1,-4)

iii) x=-2 ; $y=(-2)^2-2(-2)-3 = 4+4-3 =5$ ;(-2,5)

Now we plot them on coordinate axis and line them to form our parabola

When we plot them we see that we have two coordinates (2,-3) and (-2,5) are common , on which our graphs are intersecting. These coordinates are solution to the two graphs.

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4 years ago