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3 years ago

The state of matter for an object that has neither definite shape nor definite volume is

Chemistry

1 answer:

padilas [110]3 years ago

5 0

Answer:

Gas

Explanation:

You cant measure the volume of gas nor can you see the shape of gas

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NEED HELP ASAP PLEASE!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

erastovalidia [21]

i think it is B. Magnetism is a force that acts at a distance and cannot be seen.

5 0

3 years ago

A 7.32 g sample of copper is contaminated with 0.81 g of zinc. Suppose an atomic mass measurement was performed on this sample.

sergejj [24]

Hope it cleared your doubt.

5 0

3 years ago

How do you read a data table?

elena-14-01-66 [18.8K]

Answer:

1st you read the column that has the subject then the tally column last you determine/read the frequency column

Explanation:

3 0

3 years ago

Using the bond energy data from your text (or the internet), determine (show calculations for) the approximate enthalpy change ,

aleksley [76]

Answer:

∆H= 438 KJ/mol

Explanation:

First, we have to find the energy bond values for each compound:

-) Cl-Cl = 243 KJ/mol

-) F-F = 159 KJ/mol

-) F-Cl = 193 KJ/mol

If we check the reaction we can calculate the number of bonds:

$Cl_2_(_g_)~+~3F_2_(_g_)~->~2ClF_3_(_g_)$

In total we will have:

-) Cl-Cl = 1

-) F-F = 3

-) F-Cl = 6

With this in mind. we can calculate the total energy for each bond:

-) Cl-Cl = (1*243 KJ/mol) = 243 KJ/mol

-) F-F = (3*159 KJ/mol) = 477 KJ/mol

-) F-Cl = (6*193 KJ/mol) = 1158 KJ/mol

Now, we can calculate the total energy of the products and the reagents:

Reagents = 243 KJ/mol + 477 KJ/mol = 720 KJ/mol

Products = 1158 KJ/mol

Finally, to calculate the total enthalpy change we have to do a subtraction between products and reagents:

∆H= 1158 KJ/mol-720 KJ/mol = 438 KJ/mol

I hope it helps!

7 0

3 years ago

If you were to use Lewis theory to predict the formula for the compound between rubidium and fluorine, it would most likely be:

goldenfox [79]

Answer: The formula of the compound formed between rubidium and fluorine is RbF

Explanation:

Ionic bond is defined as the bond which is formed by complete transfer of electrons from one atom to another atom.

The atom which looses the electron is known as electropositive atom and the atom which gains the electron is known as electronegative atom. This bond is usually formed between a metal and a non-metal.

Rubidium is the 37th element of the periodic table having electronic configuration of $1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^1$

This will loose 1 electron to form $Rb^+$ ion

Fluoride is the 9th element of the periodic table having electronic configuration of $1s^22s^22p^5$

This will gain 1 electron to form $F^-$ ion

To form $RbF$ compound, 1 rubidium ion is needed to neutralize the charge on fluoride ion

The formation of the given compounds is shown in the image below.

4 0

3 years ago