Answer:
kinetic energy turned potential energy
Explanation:
it moves up the hill and stops so the movement is kinetic energy and the stop is potential energy
Answer:
5 m
Explanation:
We'll begin by calculating the original potential energy. This can be obtained as follow:
Mass (m) = 0.2 Kg
Height (h) = 20 m
Acceleration due to gravity (g) = 10 m/s²
Energy (E₀) =?
E₀ = mgh
E₀ = 0.2 × 10 × 20
E₀ = 40 J
Next, we shall determine the new energy of the ball.
Energy (E₀) = 40 J
Energy lost (Eₗ) = 30 J
New energy (E) =?
E = E₀ – Eₗ
E = 40 – 30
E = 10 J
Finally, we shall determine height of the ball on rebound. This can be obtained as follow:
New energy (E) = 10 J
Mass (m) = 0.2 Kg
Acceleration due to gravity (g) = 10 m/s²
Height (h) =?
E = mgh
10 = 0.2 × 10 × h
10 = 2 × h
Divide both side by 2
h= 10 / 2
h = 5 m
Thus, the height of the ball on rebound is 5 m
Answer:
The answer to the question is;
When she is 8 m from the building fast the length of her shadow on the building is decreasing at or 0.22 m/s.
Explanation:
We have
Distance of the spotlight from the building = 20 m
Distance of woman from the building when her speed is measured = 8 m
Height of the woman = 2 m
Actual speed of the woman = 0.8 m/s
Comparing the distance of the woman from the spotlight and the wall from the spotlight, we have when the woman is 8 m from the building she is 12 m from the spotlight
Therefore we have
where y is the shadow cast by the woman on the building = 10/3
When the woman is x distance from the building, she is 20 - x meters from the spotlight
Therefore the above equation can be written as
which gives finding the derivative of both sides gives
hence we have by dividing by dt gives
However we know that
Therefore
The rate of decrease of her shadow is given by
or 0.222 m/s.
Answer:
Rate at which water is being pumped into the tank,
Explanation:
Rate at which water is leaking out,
Height of the tank, h = 12 m
The top diameter of the tank, d = 8 m = 800 cm
The top radius of the tank, r = d/2 = 800/2 = 400 cm
The rate of change of water height, dh/dt = 30 cm/min
Height of water = 2 m
By carefully observing the diagram contained in the file attached to this solution, using the property of similar triangle:
h/r = 12/4
r = h/3
Since the tank is conical, volume of the water at time, t will be:
Finding the derivative of the above with respect to t to get the rate of change in the volume of water.
Answer:
two pretty best friends -
Explanation: